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wlad13 [49]
3 years ago
9

What is the area of the acute triangle given below?

Mathematics
1 answer:
vova2212 [387]3 years ago
7 0
The answer should be B. 36 sq units hoped this helps :)
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Solve the system of linear equations. 4x + 6y = 12 x + 2y = 10 The solution is​
garik1379 [7]

Answer:

x = -18, y = 14

Step-by-step explanation:

4x + 6y = 12

x + 2y = 10

Divide both sides of the first equation by 2. Write the second equation below it.

2x + 3y = 6

x + 2y = 10

Rewrite the first equation. Multiply both sides of the second equation by -2 and write below it. Then add the equations eliminating x.

      2x + 3y = 6

(+)  -2x - 4y = -20

-------------------------

             -y = -14

y = 14

Substitute 14 for y in the second equation and solve for x.

x + 2y = 10

x + 2(14) = 10

x + 28 = 10

x = -18

Solution: x = -18, y = 14

7 0
3 years ago
Find parametric equations for the path of a particle that moves along the circle x2 + (y − 3)2 = 16 in the manner described. (en
sveticcg [70]

Answer:

x(t) = 4 cos(-t)\\y(t) = 4 sin(-t) + 3\\

and t ∈ [0,2π]

Step-by-step explanation:

The standard equation for circle is:

(x-h) ^2 + (y-k)^2 = r^2

Comparing our equation with standard

x^2 + (y-3)^2 =16

h= 0,

k= 3

r= 4 (as in standard r², so r =√ r²)

Required:

Parametric equations of the circle

Formula:

x = r cos(t) + h\\y= r cos(t) +k

Putting values of r and h and k we get

x= 4 cos(t) + 0 \\x= 4 cost(t) \\y= 4 sin(t) + 3

As we need to start the object at (4,3)

x(0) = 4 and y(0) = 3

and the period is 2π

As the rotation is starting clock wise we will invert the value of t i.e -t

x(t) = 4 cos(-t)\\y(t) = 4 sin(-t) + 3\\

and t ∈ [0,2π]

5 0
3 years ago
Find area of rectangle <br> Pls help
xxTIMURxx [149]

Answer:

Step-by-step explanation:

area=l*w

7 1/2*3 1/4

15/2*13/4

=195/8

=24 3/8 pies

4 0
3 years ago
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Give the degree of the polynomial. 10yx^5w^4-w^3v^5-5x^11-6​
torisob [31]

10yx⁵w⁴ - w³v⁵ - 5x¹¹ - 6

Degree = biggest exponent = 11

4 0
3 years ago
use the information given in the diagram, tell why MN congruent to PO and &lt;nom congruent to &lt;PMO
VARVARA [1.3K]
MN is congruent to PO because triangles MPO is congruent to ONM by SAS, then corresponding sides and angles are congruent. So when two triangles are congruent corresponding sides and angles are congruent. This is reason that
7 0
4 years ago
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