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matrenka [14]
3 years ago
15

What is the solution of the inequality x/3 > 1?

Mathematics
1 answer:
Alika [10]3 years ago
6 0
If you would like to know what is the solution of the inequality x/3 > 1, you can calculate this using the following step:

x/3 > 1    /*3
x > 1 * 3
x > 3

The correct result would be x > 3.
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Find the measure of the indicated angle to the nearest degree
Alisiya [41]

Answer:

The answer to your question is below

Step-by-step explanation:

14) sin Ф = 32/33

    sin Ф = 0.9697

        Ф = 75.86°

15) sin Ф = 16/36

     sin Ф = 0.444

          Ф = 26.39°

16) sin Ф = 29/36

     sin Ф = 0.806

          Ф = 53.66°

17) cos Ф = 11/34

    cos Ф = 0.324

          Ф = 71.12°

18) sin Ф = 21/40

     sin Ф = 0.525

           Ф = 31.67°

19) cos Ф = 6/14

     cos Ф = 0.429

          Ф = 64.62°

20) cos Ф = 38/39

      cos Ф = 0.974

            Ф = 13°

3 0
3 years ago
Help me what to write a word phrase for each algebraic expression. Please help.
andrezito [222]
#1:  The sum of q and 5 
#2:  Twelve times x

Please do as many as you can by yourself and ask questions about those that are hard for you.  

3 0
3 years ago
How to solve 4+|7-m|=5
notka56 [123]
When
|a|=b
assume
a=b and -a=b
so

4+|7-m|=5
minus 4 from both sides
|7-m|=1
assume
7-m=1 and
-(7-m)=1

7-m=1
minus 7 both sidees
-m=-6
times -1 both sides
m=6

-(7-m)=1
distribute
-7+m=1
add 7 to both sides
m=8

m=6 and 8
4 0
3 years ago
2a +5 - 3a -12 please
chubhunter [2.5K]

Answer:

-7-a

Step-by-step explanation:

2a-3a +5-12

-a - 7

or -7-a

7 0
3 years ago
Read 2 more answers
Help out?? Mathematics image.
Brilliant_brown [7]

Answer: (12) ∠1 = 20° (13) ∠2 = 50° (14) ∠3 = 15° (15) UV = 80° (16) AB = 40°  (17) ABC <em>or</em>  180° - CD (18) BC - 140°  (19) ABC = 150°

<u>Step-by-step explanation:</u>

12) \frac{1}{2}(UV - ST) = ∠1

\frac{1}{2}(80 - 40) = ∠1

\frac{1}{2}(40) = ∠1

20 = ∠1

13) \frac{1}{2}(UV + ST) = ∠2

\frac{1}{2}(70 + 30) = ∠2

\frac{1}{2}(100) = ∠2

50 = ∠2

14) \frac{1}{2}(VB - BS) = ∠3

\frac{1}{2}(60 - 30) = ∠3

\frac{1}{2}(30) = ∠3

15 = ∠3

15) \frac{1}{2}(UV - ST) = ∠1

\frac{1}{2}(UV - 20) = 30

UV - 20 = 60

UV = 80

16) ∠1 = arc AB

     ∠1 = 40

              arc AB = 40

17) arc AB + arc BC = arc AC

                               = 180 = arc CD  

18) ∠1 + ∠2 + ∠3 = 180

   20 + ∠2  + 20 = 180

            ∠2 + 40 = 180

                      ∠2  = 140

19) ∠1 + ∠ 2 = arc ABC

     ∠1 + ∠2 + ∠3 = 180

    arc ABC + 30 = 180

            arc ABC = 150


4 0
3 years ago
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