Answer:
$59.96
Step-by-step explanation:
Given:
The science club has raised $154. 24 to buy food for a polar bear cub at the zoo.
It costs $53.55 to feed the cub each week.
Question asked:
How much more money does the club need to raise to feed the cub for one month (four weeks)?
Solution:
Cost of feed for the cub for 1 week = $53.55
Cost of feed for the cub for 4 weeks = $53.55
4 = $214.20
Money raised by the science club = $154. 24
More money needed by science club = Cost of feed for 4 weeks - Money raised by the science club
More money needed by science club = $214.20 - $154. 24
= $59.96
Thus, the science club will be needed $59.96 more money for one month (four weeks) feed.
Answer:
Population is all students from grades 3-12.
Sample is the students who participated in the survey.
Step-by-step explanation:
Given : A survey of third- to twelfth-grade students with a sample size of 2026 found that they devoted an average of 1 hour and 46 minutes per day to using entertainment media.
To find : Identify the population and the sample.
Solution :
The population is defined as it contain all individuals which we want to collect the information.
So, the population consists of all third- to twelfth grade students.
Therefore, Population is all students from grades 3-12.
The sample is defined as a part of population of which information was actually collected.
So, the sample is only the respondents in the survey conducted in 2026.
Therefore, Sample is the students who participated in the survey.
Answer:
4 / ($3.28) is the correct answer
Step-by-step explanation:
As cost of one box is $3.28
the cost of four boxes will be 4 divided by the cost of one box....so that why the 4/($3.28) is correct option
Answer:
90 units²
Step-by-step explanation:
The rectangular figure is 10 units wide (from -4 to +6) and 9 units high (from -4 to +5), so its area is 10·9 = 90 square units.
Answer:
The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the <u>line y = x</u> and a translation <u>10 units right and 4 units up</u>, equivalent to T₍₁₀, ₄₎
Step-by-step explanation:
For a reflection across the line y = -x, we have, (x, y) → (y, x)
Therefore, the point of the preimage A(-6, 2) before the reflection, becomes the point A''(2, -6) after the reflection across the line y = -x
The translation from the point A''(2, -6) to the point A'(12, -2) is T(10, 4)
Given that rotation and translation transformations are rigid transformations, the transformations that maps point A to A' will also map points B and C to points B' and C'
Therefore, a sequence of transformation maps ΔABC to ΔA'B'C'. The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, which is T₍₁₀, ₄₎