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4 years ago

Which of the following does NOT correctly describe the kinetic molecular theory? Collisions between gas particles are inelastic.

Chemistry

2 answers:

Sergio [31]4 years ago

7 0

Answer: Collisions between gas particles are inelastic.

Explanation: Kinetic Molecular Theory explains the basic relation between the temperature and the speed of the gaseous molecule . From this theory itself, ideal gas equation was born.

the incorrect postulates among the given is that the 'Collisions between gas particles are inelastic' because during collision, the gas molecules collide with one another as well as with the walls of the container .

Thus there is no loss of kinetic energy in the collision phenomenon .

It is also correctly given that Gas particles are small and spherical with an insignificant volume and the motion of gas particles is constant and random.

emmainna [20.7K]4 years ago

5 0

<span>Collisions between gas particles are inelastic. - A

The collisions in a gas are assumed to be perfectly elastic
</span>

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Answer:

The average mass of iron to be is 54.76 amu.

Explanation:

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

Mass of Fe-54 isotope = 53.9396 amu

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Fractional abundance of Fe-54 = 0.05845

Mass of Fe-56 isotope = 55.9349 amu

Percentage abundance of Fe-56 = 91.754 %

Fractional abundance of Fe-56= 0.91754

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Mass of Fe-58 isotope = 57.9333 amu

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Fractional abundance of Fe-58 = 0.00282

Average atomic mass of iron :

$=53.9396 amu\times 0.05845+55.9349 amu\times 0.91754 +56.9354 amu\times 0.002119 + 57.9333 amu\times 0.00282=54.76 amu$

The average mass of iron to be is 54.76 amu.

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3 years ago

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3 years ago

1. For the reaction 3A — C, the initial concentration of A was 0.2 M, and the reaction rate was

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Answer:

$r=25M^{-1}s^{-1}[A]^2$

Explanation:

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In this case, according to the given information for this chemical reaction, it is possible for us to set up the following general rate law and the ratio of the initial and the final (doubled concentration) condition:

$r=k[A]^n\\\\\frac{r_1}{r_2} =\frac{k[A]_1^n}{k[A]_2^n}$

Next, we plug in the given concentrations of A, 0.2M and 0.4 M, the rates, 1.0 M/s and 4.0 M/s and cancel out the rate constants as they are the same, in order to obtain the following:

$\frac{1.0}{4.0} =\frac{0.2^n}{0.4^n}\\\\0.25=0.5^n\\\\n=\frac{ln(0.25)}{ln(0.5)} \\\\n=2$