1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Flauer [41]
3 years ago
11

MARKING BRAINLIEST :)

Chemistry
1 answer:
Reil [10]3 years ago
3 0

Answer:

a

Explanation:

You might be interested in
Is sulfur dioxide a compound, mixture or element? Thanks!
horsena [70]
It is a compound because a compound is two or more different elements chemically combined.
5 0
3 years ago
Find the amount of heat energy needed to convert 400 grams of ice at -38°C to steam at 160°C.
Marianna [84]

The amount of heat energy needed to convert 400 g of ice at -38 °C to steam at 160 °C is 1.28×10⁶ J (Option D)

<h3>How to determine the heat required change the temperature from –38 °C to 0 °C </h3>
  • Mass (M) = 400 g = 400 / 1000 = 0.4 Kg
  • Initial temperature (T₁) = –25 °C
  • Final temperature (T₂) = 0 °
  • Change in temperature (ΔT) = 0 – (–38) = 38 °C
  • Specific heat capacity (C) = 2050 J/(kg·°C)
  • Heat (Q₁) =?

Q = MCΔT

Q₁ = 0.4 × 2050 × 38

Q₁ = 31160 J

<h3>How to determine the heat required to melt the ice at 0 °C</h3>
  • Mass (m) = 0.4 Kg
  • Latent heat of fusion (L) = 334 KJ/Kg = 334 × 1000 = 334000 J/Kg
  • Heat (Q₂) =?

Q = mL

Q₂ = 0.4 × 334000

Q₂ = 133600 J

<h3>How to determine the heat required to change the temperature from 0 °C to 100 °C </h3>
  • Mass (M) = 0.4 Kg
  • Initial temperature (T₁) = 0 °C
  • Final temperature (T₂) = 100 °C
  • Change in temperature (ΔT) = 100 – 0 = 100 °C
  • Specific heat capacity (C) = 4180 J/(kg·°C)
  • Heat (Q₃) =?

Q = MCΔT

Q₃ = 0.4 × 4180 × 100

Q₃ = 167200 J

<h3>How to determine the heat required to vaporize the water at 100 °C</h3>
  • Mass (m) = 0.4 Kg
  • Latent heat of vaporisation (Hv) = 2260 KJ/Kg = 2260 × 1000 = 2260000 J/Kg
  • Heat (Q₄) =?

Q = mHv

Q₄ = 0.4 × 2260000

Q₄ = 904000 J

<h3>How to determine the heat required to change the temperature from 100 °C to 160 °C </h3>
  • Mass (M) = 0.4 Kg
  • Initial temperature (T₁) = 100 °C
  • Final temperature (T₂) = 160 °C
  • Change in temperature (ΔT) = 160 – 100 = 60 °C
  • Specific heat capacity (C) = 1996 J/(kg·°C)
  • Heat (Q₅) =?

Q = MCΔT

Q₅ = 0.4 × 1996 × 60

Q₅ = 47904 J

<h3>How to determine the heat required to change the temperature from –38 °C to 160 °C</h3>
  • Heat for –38 °C to 0°C (Q₁) = 31160 J
  • Heat for melting (Q₂) = 133600 J
  • Heat for 0 °C to 100 °C (Q₃) = 167200 J
  • Heat for vaporization (Q₄) = 904000 J
  • Heat for 100 °C to 160 °C (Q₅) = 47904 J
  • Heat for –38 °C to 160 °C (Qₜ) =?

Qₜ = Q₁ + Q₂ + Q₃ + Q₄ + Q₅

Qₜ = 31160 + 133600 + 167200 + 904000 + 47904

Qₜ = 1.28×10⁶ J

Learn more about heat transfer:

brainly.com/question/10286596

#SPJ1

7 0
2 years ago
Which component is required for the activation of some enzymes?
shepuryov [24]
The best answer is letter A. 
The main factors that change the speed of enzymatic reactions are temperature, pH and substrate concentration (quantity). <span>There are enzymes that need other associated molecules to work. These molecules are called enzyme co-factors. They can be organic ions like mineral salts.</span>
5 0
3 years ago
Read 2 more answers
How many grams of hydrogen are needed to produce 1.80 g of water according to this equation? 2H2 + O2 → 2H2O
Arisa [49]

Hey there!:

Molar mass:

H2 = 2.01 g/mol    ;    H2O = 18.01

Given the reaction:

2 H2 + O2 = 2 H2O

2 * (2.01 ) g H2 ------------- 2 * ( 18.01 ) g H2O

mass H2 --------------------- 1.80 g H2O

mass H2 = 1.80 * 2 * 2.01 / 2* 18.01

mass H2 = 7.236 / 36.02

mass H2 = 0.2008 g


Hope that helps!

7 0
3 years ago
Pls help me !!!! Is for chemistry
Sphinxa [80]

Answer:

Explanation:

1) Molarity of the solution is (0.50/0.75)x1 = 0.66666 Mol/L

2) Molar mass of NaCl is 23+35 = 58g

Molarity = (0.5/58)/0.075 = 0.115 Mol/L

3) Molar mass of Li_{2}SO_{4} = 7x2 + 32 + 16x2 = 78g

Molarity = (734/78)/0.875 = 10.754 Mol/L

5) Molar mass of   Pb(C_{2}H_{3}O_{2})_{4}

= 207.2 + ((12x2) + (1x3) + (16x2))x4

= 207.2 + (24+3+32)x4 = 443.2g

Molarity = (0.0672/443.2)/0.1335 = 0.001135 Mol/L

6) Both are the same.

Solution 1 Molarity = 1.0/1.0 = 1 Mol/L

Solution 2 Molarity = 1.0/1.0 = 1 Mol/L

Molarities of the solutions are the same.

7 0
3 years ago
Other questions:
  • Which type of heat transfer’s keyword is Waves?
    13·1 answer
  • Two elements in the second transition series (y through cd ) have three unpaired electrons in their 3+ ions. what elements fit t
    5·2 answers
  • A(n) _____ is a natural object that orbits another object in the solar system besides the Sun.
    14·1 answer
  • "M" represents a metallic element, the oxide of which has the formula M2O. The formula of the chloride of M is..................
    10·1 answer
  • Someone please help! I will give Brainliest to who answers the best! Write an explanation of how mass determines (or affects) th
    9·1 answer
  • The specific spatial arrangement of amino acid residues that are close to each other in the polypeptide chain is called______the
    12·1 answer
  • A covalent bond is best described as ______(A) a bond between two polyatomic ions.(B) a bond between a metal and a nonmetal.(C)
    5·1 answer
  • How many moles of H2 are needed to produce 34.8 moles of NH3?
    15·1 answer
  • Which type of electromagnetic wave has the greatest wavelength?(1 point)
    13·1 answer
  • Calculate the grams of so2 gas present at stp in a 5. 9 l container. (atomic weights: s=32, o=16).
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!