Question

Two different proteins X and Y are dissolved in aqueous solution at 37 °C. The proteins bind in a 1:1 ratio to form XY. A solution that is initially 1.00 mM in each protein is allowed to reach equilibrium. At equilibrium, 0.20 mM of free X and 0.20 mM of free Y remain. What is Kc for the reaction?

Answer 1

Answer:

Kc of reaction is 20.

Explanation:

The two proteins are X and Y.

The [X] = 1mM

[Y]=1mM

At equilibrium, [X] = 0.2mM  [Y] = 0.2mM

we know that equilibrium constant is:

Kc=$\frac{[Products]}{[Reactants]}=\frac{[XY]}{[X][Y]}$

[XY]= 1-0.20=0.80 mM

putting values:

Kc=$\frac{0.80}{0.20X0.20}=20$