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Andrei [34K]
3 years ago
12

What are the factor pairs for 10?

Mathematics
1 answer:
sineoko [7]3 years ago
3 0
The pairs are 1 and 10. 2 and 5.
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In Jamie's drawer are 3 pairs of blue socks, 1 pair
Effectus [21]

Answer:

24%

Step-by-step explanation:

I think this is right. im sorry if its not but i went to a percent calculator and checked my answer. hope this helped :)

6 0
3 years ago
Which of the following gives all of the coefficients of the algebraic expression -2x2 + 17 -15x + 7xy?
Stels [109]
The answer is -15, -2,7
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lana [24]

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5 0
2 years ago
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We have two varieties of concrete that we can mix together. One is 5% water and 95% concrete mix, and the other is 20% water and
Orlov [11]

Answers:

  • <u>20 pounds</u> of the 95% concrete mix
  • <u>10 pounds</u> of the 80% concrete mix

=================================================

Explanation:

x = amount of the 95% concrete mix

y = amount of the 80% concrete mix

Type A mix has 95% concrete. If we have x pounds of this, then 0.95x pounds is pure concrete. Type B mix has 80% concrete. If there are y pounds of this, then 0.80y pounds is pure concrete.

So far we have 0.95x+0.80y pounds of pure concrete from the two mixes

Divide this over 30 to get (0.95x+0.80y)/30

Setting this equal to 0.90 means we want the final mix to be 90% concrete.

Since we want 30 pounds total, we can say x+y = 30 which solves to y = 30-x. We'll use this later

-------------------------------

(0.95x+0.80y)/30 = 0.90

0.95x+0.80y = 30*0.90 .... multiply both sides by 30

0.95x+0.80y = 27

0.95x+0.80(30-x) = 27 ..... plug in y = 30-x

0.95x+0.80*30-0.80*x = 27

0.95x+24-0.80x = 27

0.15x+24 = 27

0.15x = 27-24 ..... subtracting 24 from both sides

0.15x = 3

x = 3/0.15 ........... dividing both sides by 0.15

x = 20

y = 30-x

y = 30-20

y = 10

5 0
2 years ago
The 2003 Zagat Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United Sta
soldi70 [24.7K]

Answer:

a. P(x=0)=0.2967

b. P(x=1)=0.4444

c. P(x=2)=0.2219

d. P(x=3)=0.0369

Step-by-step explanation:

The variable X: "number of meals that exceed $50" can be modeled as a binomial random variable, with n=3 (the total number of meals) and p=0.333 (the probability that the chosen restaurant charges mor thena $50).

The probabilty p can be calculated dividing the amount of restaurants that are expected to charge more than $50 (5 restaurants)  by the total amount of restaurants from where we can pick (15 restaurants):

p=\dfrac{5}{15}=0.333

Then, we can model the probability that k meals cost more than $50 as:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{3}{k} 0.333^{k} 0.667^{3-k}\\\\\\

a. We have to calculate P(x=0)

P(x=0) = \dbinom{3}{0} p^{0}(1-p)^{3}=1*1*0.2967=0.2967\\\\\\

b. We have to calculate P(x=1)

P(x=1) = \dbinom{3}{1} p^{1}(1-p)^{2}=3*0.333*0.4449=0.4444\\\\\\

c. We have to calcualte P(x=2)

P(x=2) = \dbinom{3}{2} p^{2}(1-p)^{1}=3*0.1109*0.667=0.2219\\\\\\

d. We have to calculate P(x=3)

P(x=3) = \dbinom{3}{3} p^{3}(1-p)^{0}=1*0.0369*1=0.0369\\\\\\

6 0
2 years ago
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