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4 years ago

What type of function is represented below the tables of value??

Mathematics

1 answer:

sergey [27]4 years ago

7 0

This is a linear function. They vary directly with each other.

x increasing by 1 each time.

y increases by 4 each time.

I hope this helps!
~kaikers

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You jog 2 kilometers in 12 minutes. Your friend jogs 3 kilometers in 16.5 minutes. Who jogs faster? You jog faster. Your friend

Darya [45]

Answer:

a) Who jogs faster?

Your friend jogs faster because he jogs with a speed of 10.91 km/hr

Step-by-step explanation:

Speed = Distance(km)/Time(hours)

Question 2 How much sooner will the faster jogger finish a five-kilometer race?

Your friend's will finish a 5km race at a speed of 18.18 km/hr

Your speed is :

You jog 2 kilometers in 12 minutes.

Convert 12 minutes to hours

60 minutes = 1 hour

12 minutes = x

x = 12/60

x = 1/5 hour

Your speed is calculated as:

2km/1/5hour

= 2 km ÷ 1/5 hour

= 2 × 5

= 10 km/hr

Your friend's speed is calculated as:

Your friend jogs 3 kilometers in 16.5 minutes.

Convert 16.5 minutes to hours

60 minutes = 1 hour

16.5 minutes = x

x = 16.5/60

x = 0.275 hour

Your speed is calculated as:

3km/0.275 hour

= 10.909090909 km/hr

Approximately = 10.91km/hr

a) Who jogs faster?

Your friend jogs faster because he jogs with a speed of 10.91 km/hr

Question 2 How much sooner will the faster jogger finish a five-kilometer race?

Your friend jogs faster, hence:

3 km = 10.91 km/hr

5km = x

x = 5 × 10.91/3

x = 18.183333333 km/hr

Your friend's will finish a 5km race at a speed of 18.18 km/hr

4 0

3 years ago

What is the quotient of 36 divided by 3/4??

Harlamova29_29 [7]

36 divided by 3/4 is 48

4 0

3 years ago

Read 2 more answers

Find the derivative of tan^-1 x

k0ka [10]

<h3>I hope it is helpful for you .....</h3>

3 0

3 years ago

Which piece of additional information can be used to prove △CEA ~ △CDB?

Slav-nsk [51]

<u>Answer-</u>

<em>The correct answer is</em>

<em>∠BDC and ∠AED are right angles</em>

<u>Solution-</u>

In the ΔCEA and ΔCDB,

$m\angle BCD=m\angle ACE$

As this common to both of the triangle.

If ∠BDC and ∠AED are right angles, then $m\angle E=90=m\angle D$

Now as

∠BCD = ∠ACE and ∠BDC = ∠AED,

∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)

Then, ΔCEA ≈ ΔCDB

Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.

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3 years ago

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There are 16 friends sharing for cupcakes if they divided the cupcakes even leave so that they get four pieces of a cupcake. how

Phantasy [73]

They need 64 pieces for each of them to receive four slices.

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3 years ago