Let the number of 250g=0.25 kg jars be x and that of 500g=0.5 kg jams be y;
therefore:
total number of jars ws
x+y=511
x=511-y..........i
total mount kgs was:
0.25x+0.5y=186.5....ii
substituting i in ii
0.25(511-y)+0.5y=186.5
127.75-0.25y+0.5y=186.5
solving for y we get:
0.25y=186.5-127.75
0.25y=58.75
y=58.75/0.25
y=235 jars
and
x=511-x
=511-235
=276
hence we conclude that there was 235 jars with 0.5 kg almond and 276 jars with 0.25 kg almonds
Answer:
cannot be reduced any further, so that's the answer.
Step-by-step explanation:
Use the distance formula:

To solve this problem you must apply the proccedure shown below:
1. You have that the number of innings are expressed as a mixed number in the exercise:

2. If you want to write it as a decimal, you can convert the fraction as a decimal by dividing the numerator by the denominator and then, you must add this to the whole number part:

The answer is: 102.67
<h3>
Answer: Bottom left corner (southwest corner)</h3>

The left endpoint is x = 4, but we don't include this endpoint because of the open hole. We use a parenthesis to indicate "don't include the endpoint"
The right endpoint is positive infinity. We always use a parenthesis with either infinity since we cannot reach infinity
The interval from 4 to infinity is written as
which is like saying 
15^2x is 225x. So, we have 225x-3=245. Adding three to both sides, we get 225x=248. Dividing by 225, we have x=248/225.