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vagabundo [1.1K]
3 years ago
5

At the end of an advertising campaign, the weekly sales declined. The weekly sales y (in dollars) are modeled by the equation y

= 6,000(4-0.09x), where x is the number of weeks after the end of the campaign.
2A) Determine the sales at the end of the campaign.

A)$6,000

B)$8,000

c)$24,000

d)$1,000
Mathematics
1 answer:
kkurt [141]3 years ago
8 0

Answer:

c)$24,000

Step-by-step explanation:

The function that models the decline of the sales is

y = 6000(4 - 0.09x)

where x is the number of weeks after the end of the campaign.

At the end of the campaign, will be no more weeks left.

So we x=0, and solve for y,

y = 6000(4 - 0.09 \times 0) \\ y = 6000(4 -0) \\ y = 6000(4) = 24000

The correct answer is c)$24,000

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Step-by-step explanation:

4 0
3 years ago
Hey can you help me answer this question by giving me the answer?
Leto [7]

The value of f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Given a function f(x)=4-2x+6x^{2}.

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6a^{2} (By just putting x=a).

f(a+h)==4-2(a+h)+6(a+h)^{2}

=4-2a-2h+6(a^{2} +h^{2} +2ah)

=4-2a-2h+6a^{2} +6h^{2} +12ah

=6a^{2} +6h^{2}-2a-2h+12ah

[f(a+h)-f(a)]/h=[6a^{2} +6h^{2}-2a-2h+12ah-(4-2a+6a^{2} )]/h

=(6a^{2} +6h^{2} -2a-2h+12ah)/h

=(6h^{2} -2h+12ah)/h

=6h+12a-2.

Hence the value of function f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Learn more about function at brainly.com/question/10439235

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