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Rudiy27
2 years ago
13

A vertical pole is supported by a wire that is 26 feet long. If the wire is attached to the ground 24 feet away from the base of

the pole, how many feet up the pole should the wire be attached?

Mathematics
1 answer:
Andrei [34K]2 years ago
8 0

The answer is in the attachment

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Which linear function represents the line given by the point-slope equation y + 7 = -2/3 (x + 6)?
PolarNik [594]
Got this from someone else but it answers your question

O f(x) = -x-1
Step-by-step explanation:
We want to isolate the 'y' variable, so we will subtract 7 from both sides.
y = x + 6 - 7
y = x -1

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6 0
2 years ago
Let f(x)=3x+5 and g(x)=x^2 find f(x).g(x)
Alina [70]
Assuming you want them multiplied


f(x)*g(x)=(3x+5)(x^2)=3x³+6x²
6 0
3 years ago
300 ml of pure alcohol is poured from a bottle containing 2 l of pure alcohol. Then, 300 ml of water is added into the bottle. A
Ede4ka [16]

Answer:

The present percentage of pure alcohol in the solution is 72.25% of pure alcohol

Step-by-step explanation:

The volume of pure alcohol poured from the 2 l bottle of pure alcohol = 300 ml of pure alcohol

The volume of water added into the bottle after pouring out the pure alcohol = 300 ml of water

The volume of diluted alcohol poured out of the bottle = 300 ml of diluted alcohol

The volume of water added into the bottle of diluted alcohol after pouring out the 300 ml of diluted alcohol = 300 ml of water

Step 1

After pouring the 300 ml of pure alcohol and adding 300 ml of water to the bottle, the percentage concentration, C%₁ is given as follows;

C%₁ = (Volume of pure alcohol)/(Total volume of the solution) × 100

The volume of pure alcohol in the bottle = 2 l - 300 ml = 1,700 ml

The total volume of the solution = The volume of pure alcohol in the bottle +  The volume of water added = 1,700 ml + 300 ml = 2,000 ml = 2 l

∴ C%₁ = (1,700 ml)/(2,000 ml) × 100 = 85% percent alcohol

Step 2

After pouring out 300 ml diluted alcohol from the 2,000 ml, 85% alcohol and adding 300 ml of water, we have;

Volume of 85% alcohol = 2,000 ml - 300 ml = 1,700 ml

The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol = 85/100 × 1,700 = 1,445 ml

The total volume of the diluted solution = The volume of the 85% alcohol in the solution + The volume of water added

∴ The total volume of the twice diluted solution = 1,700 ml + 300 ml = 2,000 ml

The present percentage of pure alcohol in the solution, C%₂ = (The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol)/(The total volume of the diluted solution) × 100

∴ C%₂ = (1,445 ml)/(2,000 ml) × 100 = 72.25 %

The present percentage of pure alcohol in the solution, C%₂ = 72.25%

3 0
3 years ago
Help will be greatly appreciated!!! Write the system of equations for these two lines.
Darya [45]

Answer:

See answer below:

Step-by-step explanation:

Blue: y=2x+1

Red: y=3x-2

5 0
2 years ago
I need help like asap thank youuu
zlopas [31]

CD = √50

....................

....................

7 0
2 years ago
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