All categories

3 years ago

Help on solving for x

Mathematics

1 answer:

Law Incorporation [45]3 years ago

4 0

$\dfrac{x}{e^5}=e^{-4}|\cdot e^5\\
x=e^{-4}\cdot e^5\\
x=e\approx2.72


$

You might be interested in

PLEASE HELP!! #8<br> k(x)=4x-2 on [3, 3+h]

zlopas [31]

X=h/4+5/4 is the correct answer

4 0

3 years ago

Write the following fraction as a decimal 6/5

steposvetlana [31]

Answer:1.2

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

How much water does it take to completely fill a pool that is 50m long, 25m wide, and 2 m deep?

viktelen [127]

Answer:

which is the volume of the water

it implies , volume=l*b*h

50m*25m*2m

2500m'3

6 0

3 years ago

Read 2 more answers

I'm really lost on this problem

Alenkinab [10]

Since you need a little bit of trigonometry to solve this problem,
I'm pretty sure you've had a little bit of trigonometry in class before
you were assigned to solve this problem.

-- The shaded triangle comes from taking the equilateral triangle and
either folding it in half or cutting it in half.

-- The base that the new triangle is standing on is 1/2 the base of the
equilateral triangle, so it's 7 cm long.

-- The acute angle at the right end of the base is the same as it was in
the equilateral triangle . . . 60 degrees.

-- The tangent of 60 degrees is (opposite side)/(adjacent side) = x / 7 cm

tan(60) = x/7

-- Multiply each side of this little equation by 7 : 7 tan(60) = x

If you don't have the tangent of 60 degrees in your pocket, you can
find it with your calculator. Multiply it by 7, and Shazam, you know 'x' .

5 0

3 years ago

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$