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Marina CMI [18]

3 years ago

7

What is angle i,t and what's x equal??

2 answers:

Sauron [17]3 years ago

8 0

This is the kite. The kite has two pairs of sides of equal length.

TE = TI and KE = KI.

Therefore we have the equation:

14x - 19 = 12x + 35 |add 19 to both sides

14x = 12x + 54 |subtract 12x from both sides

2x = 54 |divide both sides by 2

x = 27

IT = 12x + 35

put the value of x to the expression:

IT = 12(27) + 35 = 324 + 35 = 359

JulijaS [17]3 years ago

6 0

in a Kite, one has two pairs of opposite angles that are equal, namely ∡K=∡T, and ∡I = ∡E, and that also means that the sides IT = ET, therefore

$\bf \stackrel{IT}{12x+35}=\stackrel{ET}{14x-19}\implies 54=2x\implies \cfrac{54}{2}=x\implies \blacktriangleright 27 = x\blacktriangleleft \\\\\\ IT=12(27)+35\implies IT=324+35\blacktriangleright \implies IT=359 \blacktriangleleft$

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If 569 people voted in the election how many were over 65 years old

Debora [2.8K]

Number of people voted given is wrong.

Question:

If 596 people voted in the election how many were over 65 years old.

The image of the problem is attached below.

Answer:

Number of people voted 65 years old = 149

Solution:

Number of people voted in the election = 596

Let us first write the formula for the part value when percentage is given.

$\text {Part value}=\frac{\text {Percentage}}{100} \times \text {Whole}$

$$=\frac{25}{100}\times596$

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A rectangular storage container with an open top is to have a volume of 10 m3 . then length of its base is twice the width. mate

katrin [286]

Answer:

The cost of materials for the cheapest such container is $163.54.

Step-by-step explanation:

A rectangular storage container with an open top is to have a volume of 10 m³.

The volume of the rectangle is

$\text{Volume} =\text{Length} \times \text{Width} \times \text{Height}$

Length of its base is twice the width.

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Length is l=2w.

Height be 'h'.

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According to question,

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i.e. Cost is given by,

$C=10(L\times W)+6(2\times L\times H+2\times W\times H)$

$C=10(2w\times w)+6(2\times 2w\times \frac{5}{w^2}+2\times w\times \frac{5}{w^2})$

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To get the minimum value,

Differentiate the cost w.r.t 'w',

$C'(w)=20\frac{d(w^2)}{dw}+180\frac{d(w^{-1})}{dw}$

$C'(w)=20\times 2w-180 w^{-2}$

$C'(w)=40w-\frac{180}{w^2}$

To find critical points put derivate =0,

$40w-\frac{180}{w^2}=0$

$40w=\frac{180}{w^2}$

$w^3=\frac{180}{40}$

$w=\sqrt[3]{4.5}$

$w=1.65$

We find the second derivative to minimize,

$C''(w)=40\frac{d(w)}{dw}-180\frac{d(w^{-2})}{dw}$

$C''(w)=40+360(w^{-3})$

$C''(w)>0$

As $C''(w)>0$ it is the minimum cost.

The cost is minimum at w=1.65.

Substitute the values in the cost function,

$C(1.65)=20(1.65)^2+\frac{180}{1.65}$

$C(1.65)=54.45+109.09$

$C(1.65)=163.54$

Therefore, the cost of materials for the cheapest such container is $163.54.

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Step-by-step explanation:

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