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Brrunno [24]
2 years ago
12

The area of a triangular garden can be no more than 120 square feet. The base of the triangle is 16 feet. What is the height of

the triangle?
show your work
Mathematics
2 answers:
vekshin12 years ago
8 0

Elena’s backyard is in the shape of a rectangle. She created a triangular-shaped flower bed (shown as the shaded region) to plant flowers in.

Answer:

The area of the triangular flower bed is <u>125</u> square feet. The area of her backyard that does not include the flower bed is <u>575</u> square feet.

Step-by-step explanation:

AreaOfTriangle

\left[\begin{array}{ccc}A =\frac{H_{b} B}{2}\end{array}\right]

\left[\begin{array}{ccc}A =\frac{H_{b} B}{2} = \frac{10*25}{2}\end{array}\right]

\left[\begin{array}{ccc}\frac{10*25}{2}=125 \end{array}\right]

AreaOfSquare

\left[\begin{array}{ccc}A=LW\end{array}\right]

\left[\begin{array}{ccc}A=LW=35*20\end{array}\right]

\left[\begin{array}{ccc}35*20\\=700\end{array}\right]

\left[\begin{array}{ccc}700-125\\=575\end{array}\right]

Alinara [238K]2 years ago
5 0

The height is 15 feet.

0.5xbxh<_120 (equate formula for area of triangle to 120)

0.5x16xh<_120

16xh<_240 (120 divided by 0.5)

h<_15 (240 divided by 16)

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Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon
leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = <u><em>proportion of households that have three cell phones NOT known.</em></u>

So, Null Hypothesis, H_0 : p = 30%      {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, H_A : p \neq 30%     {means that the actual percentage of households different from 30%}

The test statistics that would be used here <u>One-sample z-test for proportions;</u>

                                T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of households having three cell phones = \frac{43}{150} = 0.29

           n = sample of households = 150

So, <u><em>the test statistics</em></u>  =  \frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }  

                                     =  -0.27

The value of z test statistic is -0.27.

<u>Also, P-value of the test statistics is given by;</u>

              P-value = P(Z < -0.27) = 1 - P(Z \leq 0.27)

                            = 1 - 0.6064 = <u>0.3936</u>

<u>Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0
3 years ago
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