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grin007 [14]
2 years ago
14

How to solve for axis of symmetry for y=(x+2)(x-4)

Mathematics
2 answers:
liberstina [14]2 years ago
8 0

Answer:

x=1

Step-by-step explanation:

y=x^{2} -4x+2x-8
y=x^{2} -2x-8   (a=1, b=-2)
x=-\frac{b}{2a} =\frac{-2}{2*1}
x=1
y=(x+2)(x-4),  x=1
y=(1+2)(1-4)
y=-9

lianna [129]2 years ago
5 0

Answer:

x = 1

Step-by-step explanation:

you can first find the two zeroes

that would be

x + 2 = 0

x - 4 = 0

x = {-2, 4}

then you average them

-2 + 4 = 2

2 / 2 = 1

the aos is 1

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