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2 years ago

How to solve for axis of symmetry for y=(x+2)(x-4)

Mathematics

2 answers:

liberstina [14]2 years ago

8 0

Answer:

x=1

Step-by-step explanation:

$y=x^{2} -4x+2x-8$
$y=x^{2} -2x-8$ $(a=1, b=-2)$
$x=-\frac{b}{2a} =\frac{-2}{2*1}$
$x=1$
$y=(x+2)(x-4), x=1$
$y=(1+2)(1-4)$
$y=-9$

lianna [129]2 years ago

5 0

Answer:

x = 1

Step-by-step explanation:

you can first find the two zeroes

that would be

x + 2 = 0

x - 4 = 0

x = {-2, 4}

then you average them

-2 + 4 = 2

2 / 2 = 1

the aos is 1

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