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Firdavs [7]
3 years ago
12

Suppose in a certain state, 60% of the people have a Visa credit card, 40% have a MasterCard, and 24% have both. Let V be the ev

ent that a randomly selected individual has a Visa credit card, and M be the analogous event for a MasterCard. So P(V ) = 0.60, P(M) = 0.40, and P(V and M) = 0.24.

Mathematics
2 answers:
GREYUIT [131]3 years ago
5 0

Question Continuation

Given that an individual is selected at random and that he or she has at least one card, what is the probability that he or she has a Visa Card?

Answer:

0.79

Step-by-step explanation:

Given

P(V) = 0.6

P(M) = 0.4

P(V∩M)=0.24

The probability of having at least one card is:

P(V)+P(B)−P(V∩M)=0.6 + 0.4 - 0.24 = 0.76

Denote C={ at least one card }.

So, P(C) = 0.76

The probability you need (definition of conditional probability):

Denote P(V|C)= {Probability that a person with just one card has visa card}

So, P(V|C) = P(V∩C) / P(C)

If you have a Visa card, you have at least one card, so P(V∩C)=P(V) = 0.6

So, P(V|C) = P(V)/P(C)

P(V|C) = 0.6/0.76

P(V|C) = 0.78947368421

P(V|C) = 0.79 ---------- Approximated

REY [17]3 years ago
3 0

Answer:

The question has some details missing; i.e

a. What is the probability that the shopper has neither type of card?

b. What is the probability that the shopper has both types of card?

c. What is the probability the individual has a Visa card but not a Mastercard? (Hint: You will use the answer)

a) 0.24

b) 0.24

c) 0.36

Step-by-step explanation:

The detailed steps is shown in the attachment.

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7 0
2 years ago
Solve 5x^2-2=-12 by taking the square root
k0ka [10]

Answer:

x = ±i√2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
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  • Left to Right  

Equality Properties

Multiplication Property of Equality

Division Property of Equality

Addition Property of Equality

Subtraction Property of Equality<u> </u>

<u>Algebra II</u>

Imaginary root <em>i</em>

  • <em>i</em> = √-1

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

5x² - 2 = -12

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Addition Property of Equality] Add 2 on both sides:                                    5x² = -10
  2. [Division Property of Equality] Divide 5 on both sides:                                 x² = -2
  3. [Equality Property] Square root both sides:                                                    x = ±√-2
  4. Rewrite:                                                                                                             x = ±√-1 · √2
  5. Simplify:                                                                                                             x = ±i√2
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