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2 years ago

9

Several students measure a 25MM long nail and wrote the measurement shown in the table below who's measurement has the greatest

percent error round to the nearest percent?

2 answers:

Tcecarenko [31]2 years ago

8 0

Answer: Tenicia is the highest

Step-by-step explanation:

Alisiya [41]2 years ago

3 0

Answer:

Step-by-step explanation:

like really i really needed the answer

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If h(x) = 5x -7,find the h(14)

Mrac [35]

B. That is the correct answer because h(14) = 63 when you divide it by 3

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3 years ago

LeRoy cut a length of string into 30

sukhopar [10]

Answer:

390 inches long

Step-by-step explanation:

The string = x

$\frac{x}{30} = 13$

$30 (\frac{x}{30} ) = 30(13)$

x = 390 inches

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3 years ago

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

erma4kov [3.2K]

Answer:

$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Step-by-step explanation:

Given

5 tuples implies that:

$n = 5$

$(h,i,j,k,m)$ implies that:

$r = 5$

Required

How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

$^{n}C_r => ^{n + 4}C_5$

$^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}$

$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

<u><em>Solved</em></u>

6 0

3 years ago

Please help! xoxo (one question)

Andreas93 [3]

Answer:

C

Step-by-step explanation:

Attachment

6 0

3 years ago

Find the hypotenuse (c) of the right triangle.

Aleksandr-060686 [28]

<h2><u>Solution</u>:-</h2>

Hypotenuse (x) of the right triangle = $\sqrt{7² \: + \: 11²}$

Hypotenuse (x) of the right triangle = $\sqrt{49 \: + \: 121}$

Hypotenuse (x) of the right triangle = $\sqrt{170}$

Hypotenuse (x) of the right triangle = 13

The hypotenuse (x) of the right triangle is <u>1</u><u>3</u><u> </u><u>m</u>.

<h3>Hence, option (D) <u>1</u><u>3</u><u> </u><u>m</u> is correct. [Answer]</h3>

4 0

3 years ago