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2 years ago

PLEASE HELP Y=4x1.5^x

Mathematics

1 answer:

kirill115 [55]2 years ago

5 0

The answer isssssssssssss that lols hope it helped2/68

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A group of children, adults, and senior citizens attended three different art exhibits that have different ticket prices for eac

crimeas [40]

Answer:

c = 100, a = 50, s = 20

Step-by-step explanation:

following information is missing from the question

6c + 7a + 2s = 990

3c + 3a + 4s = 430

2c + 4a + 4s = 480

If you solve the equation by putting in the values given in the option you will deduce that only option d matches LHS to the RHS

Lets see how,

6c + 7a + 2s = 990

where, c = 100, a = 50, s = 20

6(100) + 7(50) + 2(20) = 990

600 + 750 + 40 = 990

990 = 990 hence true

2c + 4a + 4s = 480 where, c = 100, a = 50, s = 20

2 (100) + 4 ( 50) + 4 (20) = 480

200 + 250 + 80 = 480

See for the other option too with the same steps done above to have a more clear understanding :)

5 0

2 years ago

Can you please answer the question above - worth 20 points - Thank You!

bonufazy [111]

Yes because you see the answer and kind of estimate how big the answer with be or how small.

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2 years ago

Sarah had 1/2 gallon of ice cream and wants to divide it into one cup servings to share with her class. A cup is one-sixteenth o

sergey [27]

She needs 8 serving dishes because you can only make 8 one cup servings out of a half gallon of ice-cream.

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3 years ago

The probability that a call received by a certain switchboard will be a wrong number is 0.02. Use the Poisson distribution to ap

MAXImum [283]

Answer:

0.2008 = 20.08% probability that among 150 calls received by the switchboard, there are at least two wrong numbers.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

The probability that a call received by a certain switchboard will be a wrong number is 0.02.

150 calls. So:

$\mu = 150*0.02 = 3$

Use the Poisson distribution to approximate the probability that among 150 calls received by the switchboard, there are at least two wrong numbers.

Either there are less than two calls from wrong numbers, or there are at least two calls from wrong numbers. The sum of the probabilities of these events is 1. So

$P(X < 2) + P(X \geq 2) = 1$