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timofeeve [1]
3 years ago
12

Attached please find my maths problem to be solved and graphed

Mathematics
1 answer:
ki77a [65]3 years ago
8 0

Answer:

Attached is the sketch

X-axis intersections:

(-3,0)

(0,0)

(1,0)

Points of inflection:

(-1,319,-2.881) Concave upward

(0.569,1.041) Concave downward

Step-by-step explanation:

Desmos (I'm not allowed to post the link, pls search it up) is a great help for these type of problems!

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28 POINTSS <br> please help with the LAST QUESTION PLEASEEE
daser333 [38]

Answer

<u><em>Unit rate mean that how many things are in a unit,for saying if we have 5 bears in each unit the unit would be 5.</em></u>

6 0
3 years ago
Select the correct answer. What is the equation of the line that has a slope of 3 and goes through the point (-3,-5)? A. y = 3x
Rus_ich [418]
Y=Mx+b
M=3
Now you need b, so plug the x-coordinate and y-coordinate into the x and y in the equation to find the b.
-5=3(-3)+b
-5=-9+b
Add 9 to both sides to isolate the b
-5=-9+b
+9. +9
4=b
So the equation is
Y=3x+4
8 0
3 years ago
Help pls??????????????????????????????????????????????????????????
rosijanka [135]

Answer:

I would probably say independent but idk

3 0
3 years ago
6/7 closer to 1/2 or
valkas [14]
6/7 in decimal form is about 0.857
1/2 in decimal form is 0.5
1 is, of course, 1
0.857 (6/7) is closer to 1 than it is closer to 0.5 (1/2)—simply subtract to see. 
Hope this helps!!
7 0
3 years ago
Read 2 more answers
A simple random sample of 85 students is taken from a large university on the West Coast to estimate the proportion of students
ahrayia [7]

Answer:

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(0.4958 , 0.7041)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the sample size 'n' = 85

The sample proportion

            p = \frac{x}{n} = \frac{51}{85} = 0.6

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(p^{-} -Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} +Z_{0.05} \sqrt{\frac{p(1-p)}{n} })

<u><em>Step(ii):-</em></u>

Given that the level of significance

α = 0.05

Z₀.₀₅ = 1.96

(0.6 -1.96 \sqrt{\frac{06(1-06)}{85} } , 0.6 +1.96 \sqrt{\frac{0.6(1-0.6)}{85} })

(0.6 - 0.104138 , 0.6 +0.104138)

(0.4958 , 0.7041)

<u><em>Final answer:-</em></u>

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(0.4958 , 0.7041)

6 0
3 years ago
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