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yan [13]
3 years ago
11

What is ten times greater than 563,626

Mathematics
2 answers:
denpristay [2]3 years ago
6 0
Answer: 5,636,260. Just add a zero behind and it's done! :)
m_a_m_a [10]3 years ago
6 0
The answer to your question is: 5,636,200.0
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Inventor A had 630 inventions, 600% more than the number of inventions inventor B had. How many inventions did B have?
skelet666 [1.2K]

Answer:

105 inventions

Step-by-step explanation:

Find how many inventions Inventor B had by dividing 630 by 6:

630/6

= 105

So, Inventor B had 105 inventions

6 0
3 years ago
Alberto is painting a large triangle on one wall of his bedroom. The base of the triangle is 4 ft, and the height is 8 ft. It ta
N76 [4]

Answer:   3.2 qts

Step-by-step explanation:

A=1/2 * b *h

1/2 * 4*8 = 16 square foot

Area is 16 square foot

Multiply the area by the quarts of paint it takes to cover 1 square foot.

16 * 0.2 = 3.2 qts

4 0
3 years ago
X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
cluponka [151]

Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

4x^4-11x^2+9=2

4x^4-11x^2+7=0

x^4-11x^2+28=0

(x^2-7)(x^2-4)=0

(4x^2-7)(x^2-1)=0

4x^2-7=0

4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

x^2-1=0

x^2=1

x=\pm1

y=2x^2-3

y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

4 0
2 years ago
What is In algebraic expression
IgorLugansk [536]

Expression without an equal sign with at least one variable

Hope this helps!

5 0
3 years ago
Can someone please help me out with my grades are bad
dolphi86 [110]

Answer:

Step-by-step explanation:

In a dilatation for find the new coordinates we have to multiply the initial value for the the scale factor

A’(-3, 12)

B’(9,6)

C’(-9,-3)

so the general rule is:

(x,y) -> (3x, 3y)

7 0
3 years ago
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