Question

A random sample of 100 undergraduate students at a university found that 78 of them had used the university library’s website to find resources for a class. What is the margin of error for the true proportion of all undergraduates who had used the library’s website to find resources for a class?

Answer 1

From the given values, it seems as if the missing key to value here is not the margin of error, but instead, the standard error. The formula for standard error is as follows:

SE = sqrt ( x(n-x)/n^3 )

Substituting the given values:

SE = sqrt ( 78(100-78)/100^3)) = 0.04

Answer 2

the answer is A on plato