Answer:
Option b) is the answer
Step-by-step explanation:
A function from X₁ to Y₁ is an object f such that every x in X₁ is uniquely associated with an object f(x) = y in Y₁.
Then
1(b)f={(5,25),(10,5),(15,5),(20,10),(5,25)} is the correct answer.
It follows that
f(5) = 25
f(10) = 5
f(15) = 5
f(20) = 10
It's C.
All the other options are a 3 to 1 ratio, except for C.
250 * 0.20 = $50 sale
250 - 50 = $200
You will pay $200 after sale
a. Find the probability that an individual distance is
greater than 214.30 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (214.30 – 205) / 8.3
z = 1.12
Since we are looking for x > 214.30 cm, we use the
right tailed test to find for P at z = 1.12 from the tables:
P = 0.1314
b. Find the probability that the mean for 20 randomly
selected distances is greater than 202.80 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (202.80 – 205) / 8.3
z = -0.265
Since we are looking for x > 202.80 cm, we use the
right tailed test to find for P at z = -0.265 from the tables:
P = 0.6045
c. Why can the normal distribution be used in part (b),
even though the sample size does not exceed 30?
I believe this is because we are given the population
standard deviation sigma rather than the sample standard deviation. So we can
use the z test.
