Answer:
16% probability that the facility needs to recalibrate their machines.
Step-by-step explanation:
We have to use the Empirical Rule to solve this problem.
Empirical Rule:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
What is the probability that the facility needs to recalibrate their machines?
They will have to recalibrate if the number of defects is more than one standard deviation above the mean.
We know that by the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean. The other 100-68 = 32% is more than 1 standard deviation from the mean. Since the normal distribution is symmetric, of those 32%, 16% are more than one standard deviation below the mean, and 16% are more than one standard deviation above the mean.
So there is a 16% probability that the facility needs to recalibrate their machines.
Answer:
t = 8.31 years
Step-by-step explanation:
This is compound growth with a growth rate of 5%, initial count of 600 and final count of 900.
The appropriate equation is P = Po (1 + 0.05)^t, where t represents the number of years required for the population to reach P:
900 = 600 (1.05)^t. Let's solve this for t:
Dividing both sides by 600, we get 900/600 = 1.05^5, or
1.5 = 1.05^t.
To solve for t, take the log of both sides:
ln 1.5 = t*ln 1.05, or
t = (ln 1.5) / (ln 1.05)
This evaluates to t = 8.31 years.
The answer is a, you add the numbers up get 4.22 which is equivalent to 4 whole aka ones and since .22 is a decimal you use your tenths and hundredths
Answer:
Step-by-step explanation:
10 divided by 12= 0.83
0.83 times 5= 4.16 or 26/625
Answer:
See below
Step-by-step explanation:
Because 2*3=6, then 2^4 * 3^4 = 6^4 since (2*3)^4 = 6^4 -> 2^4 * 3*4 = 6^4
