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Alex73 [517]
3 years ago
8

Which function best models the data in the graph?

Mathematics
2 answers:
Alex777 [14]3 years ago
8 0
I g=2.04x
O y=10.2/x
Tju [1.3M]3 years ago
6 0

Answer:

y= 10.2\sqrt{x}   Also, next part is 96 lbs.

Step-by-step explanation:

Just did it on edgen and got both right

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I need helpp will give brainliesst!!!
Irina18 [472]

Answer:

C) 7c+6s-63

Step-by-step explanation:

set up this equation because you are adding the two expressions

7c-18+6s-45

combine like terms

7c+6s-63

4 0
3 years ago
What is the greatest common factor of 150, 275 and 420
larisa [96]

Answer:

I believe the answer is 5!

Step-by-step explanation:

3 0
3 years ago
Which description does this model and equation represent? A)Area of a square as the sides increase by 1 unit
zaharov [31]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t-16t^2.

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}

(\text{Average velocity})_{0.1\ s}=696\ ft/s

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}

(\text{Average velocity})_{0.01\ s}=7536\ ft/s

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}  

(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}

(\text{Average velocity})_{0.001\ s}=75936\ ft/s

5 0
3 years ago
Plz tell me the aswer and how you worked it out. A tree grows to a height of 13.75m over 5 1/2 years. What is the average annual
marin [14]
1. Take your 13.75 and 5 1/2 and put it into a dividing table 
           _______
     5.5 I13.75               

                              you need to get your decimal out of deviser (5.5) will now be (55) because you moved the decimal over there you also need to move the decimal that is on the inside to and it will be (137.5)

2. When you divide you would get 2.5 

3. Now you would know how much the tree grew over the 5 1/2 years.

ANSWER:  2.5m a year!

Hope this helped! 

:)
4 0
3 years ago
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