Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
12 down is decagon. 7 down is mode. I think 5 down is slope. 13 down is prime. 3 down might be variable. 10 down should be equation. Hope these are right!
Answer:
(22.12, 27.48)
Step-by-step explanation:
Given : Significance level : 
Sample size : n= 8 , which is a small sample (n<30), so we use t-test.
Critical values using t-distribution: 
Sample mean : 
Standard deviation : 
The confidence interval for population means is given by :-
i.e. 
Hence, the 95% confidence interval, assuming the times are normally distributed.= (22.12, 27.48)
Answer:
the second equation converted to slope-intercept form is y = -1/3x -1
Step-by-step explanation:
