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2 years ago

Please awnser in link below

Mathematics

2 answers:

xenn [34]2 years ago

8 0

Answer:

You will get 13 groups.

Step-by-step explanation:

324 / 24 = 13.5 So there are 13 groups with 5 left over. Hope this helps.

12345 [234]2 years ago

7 0

Answer:

13 groups of 24

Step-by-step explanation:

324/24 = 13.5

So there can be 13 groups of 24 with 5 left over

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Please help! both questions

BlackZzzverrR [31]

A)
f(2x)+g(3x-9)

2fx+g(3x)+g•-9

2fx+3gx+g•-9

Answer:2fz+3gz-9g

5 0

2 years ago

Find the slope given points (3,2) (4,7)

snow_lady [41]

Answer: The slope is 5.

Step-by-step explanation: Use formula: (y2-y1)/(x2-x1)

(7-2)/(4-3)

5/1 = 5

Have a nice day! :)

6 0

2 years ago

A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha

ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students received a passing grade = 77%

n = sample of tests = 40

p = population proportion

Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ , $0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ ]

= [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0

2 years ago

Write this polynomial in standard form :8x^2 - 4x^3 + 12 - 5x

rodikova [14]

Hello from MrBillDoesMath

Answer: -4x^3 + 8x^2 -5x + 12

Discussion:

Standard for for a polynomial meas tne power of x descend so standard fro of

8x^2 - 4x^3 +12 -5x is

-4x^3 + 8x^2 -5x + 12

Note: the problem statements shows this ":8x^2". I didn't know how to deal with the ":" character so simply ignored it.

Thank you,

Mr. B

3 0

3 years ago

Josh spent $42 on snacks.Maia spend $48 on hotdogs and hamburgers.Max spent 35 on rolls,condiments,lettuce,and tomatoes,and Mark

Andrei [34K]

Answer:

$165

Step-by-step explanation:

Money spent:

Josh=42

Maia=48

Max=35

Mark and Victoria = 40

35 + 40 + 42 + 48 = $165

3 0

3 years ago

Read 2 more answers