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bija089 [108]
3 years ago
15

I rlly hate math, pweaseeee help me asap!!!

Mathematics
1 answer:
jekas [21]3 years ago
6 0

Answer:

See explanation.

Step-by-step explanation:

Part C)

5+(-10)

When adding a positive to a negative, the result will be the sign of the larger absolute value. In this case, 10 is greater than 5, so the result will be negative.

Adding a negative is also the same thing as subtracting a positive.

5+(-10)\\5-10\\-5

For your second problem, 5 is larger than 3, so the result will be positive.

5+(-3)\\5-3\\2

-----

When adding a positive to another positive, the result will be positive.

5+3\\8

When adding a number to zero, the answer will always be the number.

5+0\\5

Part D)

When multiplying a positive times a negative, the result will always be negative.

5*(-10)\\-50

5*(-3)\\-15

-----

When multiplying a positive times a positive, the result will always be positive.

5*10\\50

When multiplying a positive or a negative times zero, the result will always be zero.

5*0\\0

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curtis threw 15 darts at a dart board and 40% of his darts hit the bulls eye how many darts missed the bulls eye
ioda

Answer:

9

Step-by-step explanation:

40 -100 = 60 and 60 percent of 15 is 9

3 0
3 years ago
X^2+2y=19<br> X^2+y^2=34
Katen [24]

Answer:

x=3

y=5

Step-by-step explanation:

3×3=9

5×5=25

9+25=34

[3^2+5^2=34]

3^2=9

2×5=10

9+10=19

[3^2+2×5=19]

5 0
3 years ago
If
Tju [1.3M]

Answer:

Step-by-step explanation:

Rationalize the denominator of b. So, multiply the numerator and denominator by \sqrt{x}

b = \frac{(1-2\sqrt{x}) *\sqrt{x}}{\sqrt{x}*\sqrt{x}  }=\frac{1*\sqrt{x} -2\sqrt{x} *\sqrt{x} }{\sqrt{x} *\sqrt{x} }\\\\=\frac{\sqrt{x} -2x}{x}\\

Now, find a +b

a +b = \frac{2x+\sqrt{x} }{x}+\frac{\sqrt{x} -2x}{x}\\\\=\frac{2x+\sqrt{x} +\sqrt{x} -2x}{x}

Combine like terms

= \frac{2x-2x+\sqrt{x} +\sqrt{x} }{x}\\\\=\frac{2\sqrt{x} }{x}

Now find (a + b)²

(a +b)² = (\frac{2\sqrt{x} }{x})^{2}

          = \frac{2^{2}*(\sqrt{x} )^{2}}{x^{2}}\\\\= \frac{4* x}{x^{2}}\\\\= \frac{4}{x}

Hint: \sqrt{x} *\sqrt{x}  =\sqrt{x*x}=x

5 0
2 years ago
H=-5 and w=2, work out the value of 4h-3w
olganol [36]
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So, H=-5, W=2 and the problem is 4h-3w

To plug them in, your new equation would be 4(-5)-3(2) and simplify. So it becomes -20-6 which = -26. 

And -26 would be your answer.
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3 years ago
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Answer:

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4 0
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