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3 years ago

A cheetah ran 196 meters in 8 seconds. Select the TWO correct statements that are true if the cheetah runs at a constant rate.

Mathematics

2 answers:

Nata [24]3 years ago

6 0

Answer

. The cheetah ran 24.5 meters per second.

Step-by-step explanation:

Its that one because if you divide the meters by seconds which is 196/8 you would get 24.5 meters per second

Elenna [48]3 years ago

5 0

Answer:

Step-by-step explanation:

Answers C, D are correct

TBh i really don't know about B because i also think its B but i'm not really that sure but it could be a possibility\

If a cheetah ran 196m is 8 seconds, then 196/8 = 24.5 meters per second.

Let’s verify all answers:

A) 24.5 x 6 = 147. 147m are ran in 6 seconds, not 125.

B) 24.5 x 10 = 245. This answer is correct!

C) We’ve establishes that a Cheetah ran 24.5 meters per second. Correct!

D) Since one minute equals 60 seconds, 24.5 x 60 = 1470. Correct!

E) 24.5 x 5 = 122.5. In this time frame, a cheetah wouldn’t run 125m.

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2 years ago

Divide<br> 4^2 divided by 4^6 =

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Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

goldfiish [28.3K]

Answer:

The volume of can A is half the volume of can B.

Step-by-step explanation:

Given

Can A and Can B

Required

The true statement

For Can A, we have:

$h =8$

$r = 0.5$

The volume is:

$Volume = \pi r^2h$

This gives:

$V_A = \pi * 0.5^2 * 8$

$V_A = \pi * 2$

$V_A = 2\pi$

For Can B, we have:

$h =4$

$r = 1$

The volume is:

$Volume = \pi r^2h$

This gives:

$V_B = \pi * 1^2 * 4$

$V_B = \pi * 4$

$V_B = 4\pi$

So, we have:

$V_A = 2\pi$

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By comparison, (d) is correct

4 0

3 years ago

Dave is comparing the circumferences of several trees in his yard. The oak tree is 0.539 meters in circumference, the ash tree h

stepan [7]

Answer: c. elm

Step-by-step explanation:

Given : The circumference of the oak tree= 0.539 meters

= $0.539\times100=53.9\text{ cm}$ [∵ 1 m = 100 cm] (1)

The circumference of the ash tree= 0.509 yards

$=0.509\times3\text{ feet}$ [∵ 1 yard = 3 feet]

$=0.509\times3\times 30.48\text{ cm}$ [∵ 1 foot = 30.48 cm]

$=46.54296\approx46.54\text{ cm}$ (2)

The circumference of the elm tree = 6281.70 millimeters

$=\dfrac{6281.70}{10}=628.17\text{ cm}$ (3)

The circumference of the poplar tree = 0.000385 miles

$=0.000385 \times5280\text{ feet}$ [∵ 1 mile = 5280 feet]

$=0.000385 \times5280\times30.48\text{ feet}$ [∵ 1 foot = 30.48 cm]

$=61.959744\approx61.96\ \text{ cm}$ (4)

From (1) , (2) , (3 ) and (4) it is clear that

46.54< 53.9 < 61.96 < 628.17

Hence, the elm tree has the greatest circumference.

5 0

2 years ago