Answer:
2, 4, 5, and 6 have the same pair of solutions.
Step-by-step explanation:
1. n(n+3)(n-4) = 0
2. 2n(4n+6)(6n-4) = 0
3. 2n(6-4n)(4n-6n) = 0
4. n(2n+3)(3n-2) = 0
5. 2n(2n+3)(3n-2) = 0
6. 3n(6n+9)(9n-6) = 0
Answers:
1. n = 0, -3, 4
2. n = 0, -3/2, 2/3
3. n = 0, 3/2
4. n = 0, -3/2, 2/3
5. n = 0, -3/2, 2/3
6. n = 0, -3/2, 2/3
Answer:
<h2>x = -1</h2>
Step-by-step explanation:
I think that the value of n is -10
49/10 This is the improper way
We have the following expression:
(27a ^ 3-1) / (9a ^ 2-6a + 1)
Rewriting we have:
(27a ^ 3-1) / (9a ^ 2-6a + 1)
(27a ^ 3-1) / ((3a-1) * (3a-1))
We exclude the values that make the denominator zero:
3a-1 = 0
a = 1/3
Answer:
a valid exclusion for the algebraic fraction is:
c. a ≠ 1/3
