1. Each term in this polynomial has a common factor of :
2. Not sure what the "vertical method" is, but I would guess it refers to some way of visualizing the distributive property.
3. You can use the same approach as in (2), or recall that :
4. Recall that a difference of squares can be factored as . So
Answer:
Step-by-step explanation:
<u>Congruent Triangles</u>
The figure shows two triangles FCD and FED. One of their sides is the radius of the circle, they both form a 90° angle with the line CD and ED and they share the same segment FD.
Thus, both triangles are congruent and we have the length of a side (12 units), one common side (the hypotenuse) and one unknown leg that must be equal. Therefore
Solving
The required side FD is the hypotenuse of any of the triangles. The unknown leg can be calculated by
Or
Thus
Solving