The expression for the greatest common factor of 20 and 30 using the distributive property is 10(2 + 3)
Pounds of ice = 20
Number of cups = 30
The relation for the distributive property :
a × (b + c)
Expand ;
a × (b + c) = (a × b) + (a × c) = ab + ac
Finding the greatest common factor of 20 and 30 ;
(2 × 10) + (3 × 10)
According to the distributive property
(2 × 10) + (3 × 10) = 10(2 + 3)
Therefore, the expression for the greatest common factor is 10(2 + 3)
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Answer:
a) 1/800 or 0.00125
b) i) 0.0013
ii) 0.001
c) 60%
Step-by-step explanation:
T = [tan(2×30)+1][2cos(30)-1] ÷ (y²-x²)
T = (tan60 + 1)(2cos30 - 1) ÷ (41² - 9²)
T = (sqrt(3) + 1)(sqrt(3) - 1) ÷ 1600
T = (3-1)/1600
T = 2/1600
T = 1/800
T = 0.00125
Error: 0.002 - 0.00125
0.00075
%error
0.00075/0.00125 × 100
60%
Answer:
0.42
Step-by-step explanation:
divide 100÷42 then the answer is 0.42
1= 12.2
8=97.6
and for the last one the answer is 10 :))
Answer:
When given a percentage of growth or decay, determined the growth/decay factor by adding or subtracting the percent, as a decimal, from 1. In general if r represents the growth or decay factor as a decimal then: b = 1 - r Decay Factor. b = 1 + r Growth Factor. A decay of 20% is a decay factor of 1 - 0.20 = 0.
Step-by-step explanation:
