Question

Which equations have the same pair of solutions? Select all that apply. n(n + 3)(n - 4) = 0 2n(4n + 6)(6n - 4) = 0 0 = 2n(6 - 4n)(4 - 6n) 0 = n(2n + 3)(3n - 2) 2n(2n + 3)(3n - 2) = 0 3n(6n + 9)(9n - 6) = 0

Answer 1

Answer:

2, 4, 5, and 6 have the same pair of solutions.

Step-by-step explanation:

1. n(n+3)(n-4) = 0

2. 2n(4n+6)(6n-4) = 0

3. 2n(6-4n)(4n-6n) = 0

4. n(2n+3)(3n-2) = 0

5. 2n(2n+3)(3n-2) = 0

6. 3n(6n+9)(9n-6) = 0

Answers:

1. n = 0, -3, 4

2. n = 0, -3/2, 2/3

3. n = 0, 3/2

4. n = 0, -3/2, 2/3

5. n = 0, -3/2, 2/3

6. n = 0, -3/2, 2/3

Answer 2

Answer:

2,4,5,6

Step-by-step explanation:

$n=0,4n+6=0\implies n=-\frac{6}{4}=-\frac{3}{2}$

$6n-4=0\implies n=\frac{4}{6}=\frac{2}{3}$

n=0, $n=-\frac{3}{2},n=\frac{2}{3}$

3.$2n(6n-4)(4-6n)=0$

n=0

$6n-4=0$

$n=\frac{4}{6}=\frac{2}{3}$

$4-6n=0$

$n=\frac{4}{6}=\frac{2}{3}$

4.$n(2n+3)(3n-2)=0$

$n=0$

$2n+3=0$

$n=-\frac{3}{2}$

$3n-2=0$

$n=\frac{2}{3}$

5.$2n(2n+3)(3n-2)=0$

$n=0$

$2n+3=0$

$n=-\frac{3}{2}$

$3n-2=0$

$n=\frac{2}{3}$

6.$3n(6n+9)(9n-6)=0$

$n=0$

$6n+9=0$

$n=\frac{-9}{6}=-\frac{3}{2}$

$9n-6=0$

$n=\frac{6}{9}=\frac{2}{3}$

Answer:2,4,5 and 6 equation have same solutions.