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3 years ago

Help Please!

Mathematics

1 answer:

steposvetlana [31]3 years ago

8 0

Answer:

The answer to this question is x=2

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What’s the shade to this problem!? PLZ HELP I REALLY NEED THIS HELP!!!

Mashcka [7]

Answer:

the bottom section

Step-by-step explanation:

cause

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4 years ago

What are the solutions of 3x^2-x+4=0

guajiro [1.7K]

3x² -x+4=0

We can use quadratic formula
a=3, b= -1, c=4
$x= \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} 
\\ \\ x= \frac{1+/- \sqrt{1-4*3*4} }{2*3} 
\\ \\ x = \frac{1+/- \sqrt{-47} }{6} 

This equation does not have real roots, it has only 2 imaginary roots.$

$x= \frac{1+ \sqrt{47}i }{6} 
\\ \\ x= \frac{1- \sqrt{47}i }{6}$

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4 years ago

50w + 100 ≥ 18000 what is w

faltersainse [42]

Answer:

358

Step-by-step explanation:

set this equal to zero.

subtract 100 from 18000

divide by 50

=358

3 0

3 years ago

Read 2 more answers

What is the solution of -8/2y-8=5/y+4 - 7y+8/y^2-16

blsea [12.9K]

Answer:

Step-by-step explanation:

$Domain:\\\\2y-8\neq0\ \wedge\ y+4\neq0\ \wedge\ y^2-16\neq0\\\\2y\neq8\ \wedge\ y\neq-4\ \wedge\ y^2\neq16\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq\pm\sqrt{16}\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq-4\ \wedge\ y\neq4\\\\\boxed{y\neq-4\ \wedge\ y\neq4}\\\\===========================$

$\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-4^2}\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{(y-4)(y+4)}\qquad\text{multiply both sides by (-2)}\\\\\dfrac{8}{y-4}=-\dfrac{10}{y+4}+\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{add}\ \dfrac{10}{y+4}\ \text{to both sides}\\\\\dfrac{8}{y-4}+\dfrac{10}{y+4}=\dfrac{14y+16}{(y-4)(y+4)}$

$\dfrac{8(y+4)}{(y-4)(y+4)}+\dfrac{10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{8(y+4)+10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{use the distributive property}\\\\\dfrac{8y+32+10y-40}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{combine like terms}\\\\\dfrac{(8y+10y)+(32-40)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{18y-8}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\iff18y-8=14y+16\\\\18y-8=14y+16\qquad\text{subtract 14y from both sides}$

$4y-8=16\qquad\text{add 8 to both sides}\\\\4y=24\qquad\text{divide both sides by 4}\\\\y=8\in D$

8 0

3 years ago

How much money does 32 oz of broccoli cost

igor_vitrenko [27]

Depends on where you’re buying. do you have any more details?

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4 years ago