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artcher [175]
3 years ago
9

Help Please!

Mathematics
1 answer:
steposvetlana [31]3 years ago
8 0

Answer:

The answer to this question is x=2

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Which equation could be solved using the graph above?
nevsk [136]

Answer:

Option 3

Step-by-step explanation:

we are given the graph of a parabola

with vertex at (0,-1) and symmetrical about y axis and also open up.

Hence the equation of the graph would be transformation of y=x^2

by a vertical shift of 1 unit down.

So new equation after transformation would be

y+1=x^2

Ory=x^2-1

Hence option 3 is right choice.

Verify:

Put Solving the equation we get

x^2=1

x=±1

In the graph x intercepts are the same as -1 and 1

Hence our answer is right.

8 0
3 years ago
Read 2 more answers
What is the equation in point slope form for the line that is parallel to y=-8x-12 that contains the point (-3,3)
belka [17]

Answer:

The equation of a parallel line in point-slope form would be y - 3 = -8(x + 3)

Step-by-step explanation:

To find this, we must first note that the original slope is -8. Parallel lines have the same slope, so we know that the new line will also have the slope of -8.

Given this information, we can use the point and slope and put them into the base form of point-slope form.

y - y1 = m(x - x1)

y - 3 = -8(x - -3)

y - 3 = -8(x + 3)

3 0
3 years ago
The distane from the spice island to lisbon is 11431 nautical miles and it took magellan and took his crew 100 days to reach Lis
natulia [17]

Answer:

114.31 nautical miles per day

Step-by-step explanation:

Use formula

S=v\cdot t,

where S is the distance, t is time and v is rate.

If S=11431 nautical miles and t=100 days, then

v=\dfrac{11431}{100}=114.31\ \text{nautical miles per day}.

8 0
3 years ago
A rocket being launched has three engines that are independent of each other. The probability of an engine firing is 0.97. What
zubka84 [21]

Answer:

.0873

Step-by-step explanation:

3 0
3 years ago
Whats the answer to 2y^0-(3y)^0
mrs_skeptik [129]

Answer:

1

Step-by-step explanation:

To answer this question, we need to that any number (except zero) raised to power 0 is equal to 1. With that in mind, let's solve this:

2y^0 - (3y)^0

= 2(1) - (1)

= <u>1</u>

<em>N</em><em>o</em><em>t</em><em>e</em><em>:</em><em> </em><em>2</em><em>y</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>y</em><em>^</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>1</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>w</em><em>h</em><em>e</em><em>r</em><em>e</em><em>a</em><em>s</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>2</em><em>y</em><em>)</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>1</em>

6 0
3 years ago
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