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sergejj [24]
3 years ago
8

A = 8: b = ; C = 10. ​

Mathematics
1 answer:
lara [203]3 years ago
8 0

Answer:

b=6

a^{2}  + b^{2} = c^{2}  \\  {8}^{2} +  {b}^{2}   =  {10}^{2}  \\ 64 +  {b}^{2}  = 100  \\ 100 - 64 =  {b}^{2}  \\ 36 =  {b}^{2}  \\   \sqrt{36}  =  \sqrt{ {b}^{2} }  \\ 6 = b

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For what value of c is the relation a function?
nydimaria [60]

Answer:

{ c  ∣  c ≠  2 , 12, -1, 0, c ∈ R }

Step-by-step explanation:

Considering the set

\left\{\left(2,\:8\right),\left(12,\:3\right),\:\left(c,\:4\right),\:\left(-1,\:8\right),\:\left(0,\:3\right)\right\}

As we know that

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So, the value of c must not be equal to 2, 12, -1, 0 i.e. c ≠ 2, 12, -1, 0

Therefore,

                   { c  ∣  c ≠  2 , 12, -1, 0, c ∈ R }

7 0
3 years ago
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8 0
4 years ago
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7 0
3 years ago
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kirill [66]

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3 0
2 years ago
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