The answer for you problem is -6.
2(-7)+8
-14 +8
-6
Answer:
x = 30° and 330°
Step-by-step explanation:
Assuming the intervals is {0 , 2π} or {0° , 360°}
![tan\ x=\frac{-\sqrt{3} }{3} \\\\x=tan^{-1} (\frac{-\sqrt{3} }{3})\\\\x = -30](https://tex.z-dn.net/?f=tan%5C%20x%3D%5Cfrac%7B-%5Csqrt%7B3%7D%20%7D%7B3%7D%20%5C%5C%5C%5Cx%3Dtan%5E%7B-1%7D%20%28%5Cfrac%7B-%5Csqrt%7B3%7D%20%7D%7B3%7D%29%5C%5C%5C%5Cx%20%3D%20-30)
So it means it lies in the 2nd and 4th quadrant because tangent is negative in the 2nd and 4th quadrant
so the two solutions are
x = 30° and 330° or
![x=\frac{\pi }{6}\ radians\ \ , \ \ \frac{11\pi }{6}\ radians](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B%5Cpi%20%7D%7B6%7D%5C%20radians%5C%20%5C%20%2C%20%5C%20%5C%20%5Cfrac%7B11%5Cpi%20%7D%7B6%7D%5C%20radians)
The slope of the line is 3/4 and the y-intercept is -1
5/8 of them are not white, so 5/8 times 56, you get 35.
Answer:
B. 18 bags
Step-by-step explanation:
First you need to determine the area of the vegetable garden. The vegetable garden is a rectangle with the following dimensions:
L = 24 ft
W = 9 ft
The Formula for the area of a rectangle is:
![A = L\times W](https://tex.z-dn.net/?f=A%20%3D%20L%5Ctimes%20W)
So let's solve it:
![A = L\timesW\\A = 24 ft\times9ft\\A= 216ft^{2}](https://tex.z-dn.net/?f=A%20%3D%20L%5CtimesW%5C%5CA%20%3D%2024%20ft%5Ctimes9ft%5C%5CA%3D%20216ft%5E%7B2%7D)
With that, we can figure out how many bags of fertilizer would be needed by dividing the area of the vegetable garden by how much one bag of fertilizer covers:
![\dfrac{214ft^2}{12ft^2/bag}=18\;bags](https://tex.z-dn.net/?f=%5Cdfrac%7B214ft%5E2%7D%7B12ft%5E2%2Fbag%7D%3D18%5C%3Bbags)