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inna [77]
3 years ago
14

Solve for x 5 x − 1 = 6 x − 9

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0

Answer:

The value of x in this equation is 8.

Step-by-step explanation:

5x - 1 = 6x - 9

Subtract 6x on both sides.

-x - 1 = -9

Add 1 to both sides.

-x = -8

Divide by -1 on both sides.

x = 8

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Q is the midpoint PR.If PQ =2x and QR= x+8.What is PQ?
vovikov84 [41]

2x=x+8

Subtract x on both sides

X=8

So PQ=8

6 0
3 years ago
Alice earns simple interest of $120 at an annual interest rate of 6% for the period of 1 year. What equation shows the relations
GalinKa [24]

i = \frac{prt}{100}

with i = 120 then

p = \frac{100(120)}{6} = $2000



7 0
3 years ago
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Which of the following is the midpoint of a line segment with endpoints −4 and 7?(1 point) 1.5 0 5.5 −3
icang [17]

Answer:

1.5

Step-by-step explanation:

To find the midpoint, add the two coordinates and divide by 2

( -4+7)/2 =

3/2

1.5

The midpoint is 1.5

7 0
3 years ago
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Given: ABCD trapezoid<br> BC=1.2m, AD=1.8m<br> AB=1.5m, CD=1.2m<br> AB∩CD=K<br> Find: BK and CK
stepladder [879]

Answer:

The value of BK is 3m and the value of CK is 2.4m.

Step-by-step explanation:

Given information: ABCD trapezoid

, BC=1.2m, AD=1.8m

, AB=1.5m, CD=1.2m

, AB∩CD=K.

Using the given information draw a figure.

Two sides of a trapezoid are parallel.

Since AB∩CD=K, therefore AB and CD are not parallel, because parallel line never intersect.

AD\parallelBC

\angle KBC=\angle KAD              (Corresponding angles)

\angle KCB=\angle KDA             (Corresponding angles)

By AA rule of similarity

\triangle KBC\sim \triangle KAD

Corresponding sides of similar triangles are proportional.

\frac{KB}{KA}=\frac{KC}{KD}=\frac{BC}{AD}

\frac{x}{x+1.5}=\frac{y}{y+1.2}=\frac{1.2}{1.8}

\frac{x}{x+1.5}=\frac{1.2}{1.8}

\frac{x}{x+1.5}=\frac{2}{3}

3x=2x+3

x=3

The length of BK is 3 m.

\frac{y}{y+1.2}=\frac{1.2}{1.8}

\frac{y}{y+1.2}=\frac{2}{3}

3y=2y+2.4

y=2.4

The length of CK is 2.4 m.

5 0
3 years ago
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