Answer:
2677
Step-by-step explanation:
Let's make this easier first of all:
a^2-y^3(a-y^2)y^2
a^2-y^5(a-y^2)
a^2-ay^5+y^7
(-2)^2-(-2)(3)^5+3^7
4-(-2*243)+2187
4-(-486)+2187
4+486+2187
490+2187
2677
A-b = 43----(1)
a+b = 13----(2)
(1)+(2) 2a=56
then a=56/2= 28
so b=13-28= -15
so that the numbers are -15 and 28
Answer:
Step-by-step explanation:
xy = k
where k is the constant of variation.
We can also express the relationship between x and y as:
y =
where k is the constant of variation.
Since k is constant, we can find k given any point by multiplying the x-coordinate by the y-coordinate. For example, if y varies inversely as x, and x = 5 when y = 2, then the constant of variation is k = xy = 5(2) = 10. Thus, the equation describing this inverse variation is xy = 10 or y = .
Example 1: If y varies inversely as x, and y = 6 when x = , write an equation describing this inverse variation.
k = (6) = 8
xy = 8 or y =
Example 2: If y varies inversely as x, and the constant of variation is k = , what is y when x = 10?
xy =
10y =
y = × = × =
k is constant. Thus, given any two points (x1, y1) and (x2, y2) which satisfy the inverse variation, x1y1 = k and x2y2 = k. Consequently, x1y1 = x2y2 for any two points that satisfy the inverse variation.
Example 3: If y varies inversely as x, and y = 10 when x = 6, then what is y when x = 15?
x1y1 = x2y2
6(10) = 15y
60 = 15y
y = 4
Thus, when x = 6, y = 4.
2nd answer choice
constant of variation is xy. XY=23. If X=7 then Y=23/7.
Answer:

Step-by-step explanation:
Given:

To find: points of intersection of the given lines
Solution:
In substitution method, the system of equations is solved by expressing one variable in terms of another, as a result, removing one variable from an equation.

Put
in the equation 
![2x+8y=7\\2[\frac{1+2y}{5}]+8y=7\\ 2+4y+40y=35\\44y=35-2\\44y=33\\y=\frac{33}{44}\\ =\frac{3}{4}](https://tex.z-dn.net/?f=2x%2B8y%3D7%5C%5C2%5B%5Cfrac%7B1%2B2y%7D%7B5%7D%5D%2B8y%3D7%5C%5C%202%2B4y%2B40y%3D35%5C%5C44y%3D35-2%5C%5C44y%3D33%5C%5Cy%3D%5Cfrac%7B33%7D%7B44%7D%5C%5C%20%3D%5Cfrac%7B3%7D%7B4%7D)
Put
in the equation 
![x=\frac{1+2y}{5}\\=\frac{1}{5}[1+2(\frac{3}{4})]\\=\frac{1}{5}[1+(\frac{3}{2})]\\\\=\frac{1}{5}(\frac{2+3}{2}) \\\\=\frac{1}{5}(\frac{5}{2})\\\\=\frac{1}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%2B2y%7D%7B5%7D%5C%5C%3D%5Cfrac%7B1%7D%7B5%7D%5B1%2B2%28%5Cfrac%7B3%7D%7B4%7D%29%5D%5C%5C%3D%5Cfrac%7B1%7D%7B5%7D%5B1%2B%28%5Cfrac%7B3%7D%7B2%7D%29%5D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B5%7D%28%5Cfrac%7B2%2B3%7D%7B2%7D%29%20%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B5%7D%28%5Cfrac%7B5%7D%7B2%7D%29%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D)
Therefore,

I<span> found the graph choices: </span>
<span>Given:</span>
8 rose bouquets
6 daffodil bouquets
total of 14 bouquets
enough flowers left to make maximum of 20 bouquets.
x = additional rose bouquets
y = additional daffodil bouquets
20 maximum bouquets - 14 made bouquets = 6 additional bouquets
x + y = 6
y = 6 - x
x = 6 - y
If x = 0 then y = 6
If x = 6 then y = 0
If x = 4 then y = 2
If x = 2 then y = 4
Pls. see attachment for the correct graph.