Question

Simplify x0y-3/x2y-1

Answer 1

Simplifying $\frac{x^0y^{-3}}{x^2y^{-1}}$ we get  $=\frac{1}{x^2y^{+2}}$

Option A is correct.

Step-by-step explanation:

We need to solve: $\frac{x^0y^{-3}}{x^2y^{-1}}$

Solving:

We know that $x^0=1$

$\frac{x^0y^{-3}}{x^2y^{-1}}$

$=\frac{1.y^{-3}}{x^2y^{-1}}$

$=\frac{1}{x^2y^{-1+3}}$

$=\frac{1}{x^2y^{+2}}$

So, simplifying $\frac{x^0y^{-3}}{x^2y^{-1}}$ we get  $=\frac{1}{x^2y^{+2}}$

Option A is correct.

Keywords: Solving exponents

Learn more about Solving exponents at:

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