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bekas [8.4K]
3 years ago
5

Select the reason why these triangles are similar. If they are not, select “not similar”

Mathematics
1 answer:
larisa [96]3 years ago
8 0

Answer:

B. SAS

Step-by-step explanation:

3/1= 2.25/075

The 2 sides are congruent and the angle between them is common

B. SAS is the answer

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Westkost [7]

Answer:

two sets are said to be overlapping if they contain at least one element in common A=(1,2,3,4)and B =(4,7,1,9)are said to be overlapping sets.

Step-by-step explanation:

please answer my question I answer your question

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6 0
3 years ago
Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans
zloy xaker [14]
Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.



Part B:

The area of the square is given by

Area=(x+4)^2=x^2+8x+16

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

x^2+8x+16=6x+8 \\  \\ \Rightarrow x^2+8x-6x+16-8=0 \\  \\ \Rightarrow x^2+2x+8=0 \\  \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2}  \\  \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2}  \\  \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
7 0
4 years ago
2(x+1.25)=3,5<br><br> Find x
Arte-miy333 [17]

Step-by-step explanation:

\tt{2(x+1.25)=3.5  } ⠀

\tt{ 2x+2.5=3.5 } ⠀

\tt{ 2x=3.5-2.5 } ⠀

\tt{2x=1  } ⠀

\tt{ x=\dfrac{1}{2}=0.5 } ⠀

7 0
3 years ago
What are the intercepts of x^2+y-9=0
Dmitry_Shevchenko [17]

Answer:

Zeros

x = -3   point (-3 ,0)

x = 3   point (3 ,0)

Step-by-step explanation:

Using a graphing calculator, we can easily check the intercepts of the equation

y  = -x^2 +9

8 0
3 years ago
. Solve the following equations for x: 3x=30
pishuonlain [190]

\mathcal \pink{Answer}

\mathcal \green{3x = 30}

\mathcal \blue{ \frac{3x}{3}  =  \frac{30}{3} }

\mathcal \red{x = 10}

3 0
3 years ago
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