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3 years ago

Select the reason why these triangles are similar. If they are not, select “not similar”

Mathematics

1 answer:

larisa [96]3 years ago

8 0

Answer:

B. SAS

Step-by-step explanation:

3/1= 2.25/075

The 2 sides are congruent and the angle between them is common

B. SAS is the answer

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Can i get the answers i need them or else i fail

denpristay [2]

The answer would be all of them except for 4,4 and 3,8 i’m pretty sure

3 0

2 years ago

What is the difference of the two polynomials?

ehidna [41]

(7y² + 6xy) - (-2xy + 3)

⇒ (-1 * -2xy) + (-1 * 3) = 2xy - 3

7y² + 6xy + 2xy - 3

7y² + 8xy - 3 Choice B.

5 0

3 years ago

Read 2 more answers

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago

Solve: x^+4/x-1 = 5/x-1

AlexFokin [52]

The first step for solving this equation is to determine the defined range.
$\frac{ x^{4} }{x-1} = \frac{5}{x-1}$ , x ≠ 1
Remember that when the denominators of both fractions are the same,, you need to set the numerators equal. This will look like the following:
$x^{4}$ = 5
Take the root of both sides of the equation and remember to use both positive and negative roots.
x +/- $\sqrt[4]{5}$
Separate the solutions.
x = $\sqrt[4]{5}$ , x ≠ 1
x = - $\sqrt[4]{5}$
Check if the solution is in the defined range.
x = $\sqrt[4]{5}$
x = - $\sqrt[4]{5}$
This means that the final solution to your question are the following:
x = $\sqrt[4]{5}$
x = - $\sqrt[4]{5}$
Let me know if you have any further questions.
:)

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%7C%20%5Cfrac%7Bx%7D%7B4%7D%20%7C%20%20%3D%201" id="TexFormula1" title=" | \frac{x}{4} | =

nlexa [21]

The answer 4/4 is equal to 1.

8 0

3 years ago