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Natalija [7]
2 years ago
10

Polynomials I really need help someone please help me please

Mathematics
1 answer:
7nadin3 [17]2 years ago
7 0

Answer:

i got 3x^2-4

Step-by-step explanation:

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Please help :(((((((! <br> Which expression is equivalent to 3/64a6b7c9?
erastova [34]

Answer:

3b^7a^6c^9/64

Step-by-step explanation:

7 0
3 years ago
10. Simplify the rational expression by rationalizing the denominator. 3 sqrt 160/sqrt 1350x A) 2 sqrt 15x/15x B) 3 sqrt 160/135
Viefleur [7K]
The simplified expression by rationalizing the denominator is (C)\frac{4 \sqrt{15x} }{15x}.

First we must simplify the expression:
\frac{3 \sqrt{160} }{\sqrt{1350x} } =  \frac{12 \sqrt{10} }{15 \sqrt{6x} } =  \frac{4 \sqrt{10} }{5 \sqrt{6x} }

Then we factor the rational parts and cancel it out:
\frac{4 \sqrt{2} \sqrt{5} }{5 \sqrt{2} \sqrt{3x} } = \frac{4\sqrt{5} }{5\sqrt{3x} }

Then we rationalize the expression:
\frac{4\sqrt{5} }{5\sqrt{3x} } * \frac{\sqrt{3x} }{\sqrt{3x} } = \frac{4 \sqrt{15x} }{5*3x} = \frac{4 \sqrt{15x} }{15x}

<span>Finally, the simplified expression by rationalizing the denominator is (C)\frac{4 \sqrt{15x} }{15x}.</span>
7 0
3 years ago
(-6,8); perpendicular to y = -3/2x -1
UNO [17]

Answer:

y =  \frac{2}{3} x + 12

Step-by-step explanation:

y =  -  \frac{3}{2} x - 1

The gradient of a line is the coefficient of x when the equation of the line is written in the form of y=mx+c.

Thus, gradient of given line=-  \frac{3}{2}.

The product of the gradients of perpendicular lines is -1.

(Gradient of line)(-3/2)= -1

Gradient of line

- 1 \div ( -  \frac{3}{2} ) \\  =  - 1( -  \frac{2}{3} )  \\  =  \frac{2}{3}

Substitute m=\frac{2}{3} into y=mx+c:

y =  \frac{2}{3} x + c

To find the value of c, substitute a pair of coordinates.

When x= -6, y= 8,

8 =  \frac{2}{3} ( - 6) + c \\  \\ 8 =  - 4 + c \\ c = 8 + 4 \\ c = 12

Thus, the equation of the line is y =  \frac{2}{3} x + 12.

7 0
3 years ago
Use quadratic formula to find both solutions to the quadratic equation given below . 3x^2-5x-1=0
Rudiy27

Answer:

x1=\frac{5+\sqrt{37}} {6}

x2=\frac{5-\sqrt{37}} {6}

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

3x^{2} -5x-1=0  

so

a=3\\b=-5\\c=-1

substitute in the formula

x=\frac{5(+/-)\sqrt{(-5)^{2}-4(3)(-1)}} {2(3)}

x=\frac{5(+/-)\sqrt{37}} {6}

x1=\frac{5+\sqrt{37}} {6}

x2=\frac{5-\sqrt{37}} {6}

8 0
3 years ago
Read 2 more answers
PLEASE HELP
Otrada [13]
<span>One cm represented 11 in. in the first scale, but now 1 cm represents 12 in. in the second scale.</span>
5 0
3 years ago
Read 2 more answers
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