The sum of the squares of their ages is; 5x²
<h3>How to Solve Algebraic Word Problems?</h3>
We are told that Maria is twice the age of Miriam.
Now, of the age of Miriam is x, then we can say that;
Age of Mariam = x
Age of Maria = 2x
Now, we want to find the sum of the squares of their ages. Thus, this is expressed as;
x² + (2x)²
= x² + 4x²
= 5x²
Read more about Algebraic Word Problems at; brainly.com/question/13818690
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The complete question is;
Express in algebraic language: the sum of the squares of the ages of Maria and Miriam, if it is known that Maria is twice the age of Miriam.
Answer:
I will show all the steps to lead to the solution.
1) 10b = 5 (√c + 2) <---- starting equation
2) divide by 5 => 2 b = √c + 2
3) subtract 2 => 2b - 2 = √c
4) raise to the power 2 => (2b - 2)^2 = c, which is the expression given.
Now these are two equivalent forms:
1) extract 2 from the parentheses: c = 4 (b -1)^2
2) expand the parentheses: c = 4b^2 - 8b + 4)
Step-by-step explanation:
Choice D
= 488000
(real number)
= 4.88 × 105
(scientific notation)
<span>= 4.88e5
maybe this will help ?</span>
Answer:226.2
Step-by-step explanation
Lateral= 2πrh
H=12
R=3
2*π*3*12=226.19
Round to nearest 10th is 226.2
