Answer:
Yes, SAS.
Step-by-step explanation:
For my education system, there isn't such thing as SAS, ASA or etc. I just had to search it up what it was.
Congruent angles are angles with the same shape and size. The two triangles are congruent if you look carefully, after that I searched up and saw the different rules of triangles. I think that SAS might be the correct answer.
Answer:
) See annex
b) See annex
x = 0,5 ft
y = 2 ft and
V = 2 ft³
Step-by-step explanation: See annex
c) V = y*y*x
d-1) y = 3 - 2x
d-2) V = (3-2x)* ( 3-2x)* x ⇒ V = (3-2x)²*x
V(x) =( 9 + 4x² - 12x )*x ⇒ V(x) = 9x + 4x³ - 12x²
Taking derivatives
V¨(x) = 9 + 12x² - 24x
V¨(x) = 0 ⇒ 12x² -24x +9 = 0 ⇒ 4x² - 8x + 3 = 0
Solving for x (second degree equation)
x =[ -b ± √b²- 4ac ] / 2a
we get x₁ = 1,5 and x₂ = 0,5
We look at y = 3 - 2x and see that the value x₂ is the only valid root
then
x = 0,5 ft
y = 2 ft and
V = 0,5*2*2
V = 2 ft³
There's really no such thing as the value of a triangle.
Every triangle has three sides, three angles, a base, a height, and an area,
and there could be problems that ask us to find any one of those.
Whatever we need to find, the process is always the same:
-- Take the information that's given.
-- Gather up everything you can remember that talks about a relationship
between what you're given and what you need to find.
-- Use them together to find the missing value.
As x increases without bound, f(x) also increases without bound
Answer:
(-∞,∞)
Step-by-step explanation:
This would form a roughly parabolic shape that extends infinitely along the x-axis. It would reach a height of ³√2 on the y-axis. Because it extends infinitely left and right, it would have an infinite domain. In interval notation, this would be (-∞,∞)
