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IrinaVladis [17]
3 years ago
13

The average retirement age for a certain country was reported to be years according to an international group dedicated to promo

ting trade and economic growth. With the pension system operating with a​ deficit, a bill was introduced by the government during the summer to raise the minimum retirement age from 60 to 62. Suppose a survey of retiring citizens is taken to investigate whether the new bill has raised the average age at which people actually retire. Assume the standard deviation of the retirement age is years. Using ​, answer parts a through c below.a. Explain how Type I and Type II errors can occur in this hypothesis test. A Type I error can occur when the researcher concludes the average retirement age ? did not increase, increased, but the average retirement age ? increased. did not increase. A Type II error can occur when the researcher concludes that the average retirement age ? did not increase, increased, ?when, in? fact, the average retirement age ? did not increase. increased.b. Calculate the probability of a Type II error occurring if the actual population age is 57.4 years old. The probability of committing a Type II error is _______ . ?(Round to three decimal places as? needed.)c. Calculate the probability of a Type II error occurring if the actual population age is 58.9 years old. The probability of committing a Type II error is _______ . ?(Round to three decimal places as? needed.)
Mathematics
1 answer:
Lana71 [14]3 years ago
5 0

The missing figures in the question can be seen below.

The average retirement age = 56.1 years ...

The number of a  survey of retired citizen = 49

The standard deviation of the retirement age is 6 years.

Using alpha ∝ = 0.02

Answer:

Step-by-step explanation:

From the given options in the first question in the given information.

Type I error can take place when the researcher concludes the average retirement age <u>increased</u>, but the average retirement age <u>did not increase. </u>

A Type II error can take place when the researcher concludes that the average retirement age <u>did not increase</u>, but the average retirement age <u>increased. </u>

<u></u>

Recall that:

population mean = 56.1

sample size = 49

standard deviation = 6

At the level of significance of 0.02, using the Excel function (=Normsinv(0.02))

The critical value for z = 2.054

<u></u>

Standard error = \dfrac{\sigma}{\sqrt{n}}

=\dfrac{6}{\sqrt{49}}

= 6/7

= 0.857

The rejection region \overline X = \mu +Z_{\alpha/0.02}*\sigma_x

\overline X = 56.1+2.05374891*0.857

\overline X = 57.86

P(Type II error) is as follows:

P(\overline X < 57.86| \mu = 57.4) = P( Z< \dfrac{\overline X - \mu }{\sigma_x})

= P( Z< \dfrac{57.86-57.4}{0.857})

= P( Z< 0.537)

From z tables;

P (Type II error) = 0.704

P(Type II error) is as follows:

P(\overline X < 57.86| \mu = 58.9) = P( Z< \dfrac{\overline X - \mu }{\sigma_x})

= P( Z< \dfrac{57.86-58.9}{0.857})

= P( Z

From z tables;

P (Type II error) = 0.1124

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Anon25 [30]

Answer:

Rob saved $24 on Saturday.

Step-by-step explanation:

Given:

Rob is saving to buy a new MP3 player.

Money earned in baby sitting = $11

Money saved =$6

First we will find the Percentage of amount he saved.

Percentage of amount he saved can calculated by Amount saved divided by total money earned and then multiplying by 100.

framing in equation form we get;

Percentage of amount he saved = \frac{6}{11} \times 100 \approx 54.55\%

Now Given:

Money earned in babysitting on Saturday = $44

We need to find the Money he saved on Saturday.

Money Saved can be calculated by Percentage of amount he saved multiplying by Money earned in babysitting on Saturday and then divided by 100.

framing in equation form we get;

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Hence Rob saved $24 on Saturday.

8 0
3 years ago
Finding the area of a regular polygon​
ddd [48]
<h2><u>Solu</u><u>tion</u><u>:</u></h2>

360° ÷ 10 ÷ 2 = 18°

So the length of the decagon side is:

10 × tan18° × 2 = 20 × tan18°

The area is: ½ × 20 × tan18° × 10 × 10 = 1000 × tan18°

≈ 324.9

.: <u>3</u><u>2</u><u>4</u><u>.</u><u>9</u> is the final answer.

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1 year ago
Isabelle is using a square piece of cardboard to make a box without a lid. She cuts 2-inch squares from each corner and folds up
katrin2010 [14]

<em>The dimensions of the cardboard to make a box without a lid is 11 inches by 11 inches.</em>

<h2>Explanation:</h2>

In this problem, we have that Isabelle is using a square piece of cardboard to make a box without a lid. She cuts 2-inch squares from each corner and folds up the edges. The figure below shows this statement. The finished box has a volume (V) of 98 cubic inches, in other words:

V=98in^3

When folding up, we get the box without lip shown in the second figure. So the volume would be:

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Since te cardboard is square, then the side (s) is given by:

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Therefore:

<em>The dimensions of the cardboard to make a box without a lid is 11 inches by 11 inches.</em>

<h2>Learn more:</h2>

Volume of a box: brainly.com/question/10501080

#LearnWithBrainly

8 0
2 years ago
Read 2 more answers
−(−49) = −49 true or false?
vova2212 [387]

I hope this helps you

false

cause two negative numbers multiple must be positive

(-1).(-49)

+49

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