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Firdavs [7]
3 years ago
13

Each of three coins has two sides, heads and tails. Represent the heads or tails status of each coin by a logical variable (A fo

r the first coin, B for the second coin, and C for the third) where the logical variable is 1 for heads and 0 for tails. Write a logic function F(A, B, C) which is 1 iff exactly one of the coins is heads after a toss of the coins. Express F (as a minterm expansion. (b) as an maxterm expansion
Mathematics
1 answer:
jeka943 years ago
3 0

Answer:

(a) F(A, B, C) = AB'C' + A'BC' + A'B'C

(b) F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)

Step-by-step explanation:

(a) If F(A, B, C) = 1 iff exactly one of the coins is heads, then either

A is heads and the others are tails (AB'C')

B is heads and the others are tails (A'BC')

C is heads and the others are tails (A'B'C)

Hence, as a minterm expansion,

F(A, B, C) = AB'C' + A'BC' + A'B'C

(b) To get the corresponding maxterm expansion, we convert to binary.

F(A, B, C) = \sum (100, 010, 001) = \sum(4,2,1)

The maxterm is the product of the complements.

F(A, B, C) = \prod (0, 3, 5, 6, 7) = \prod(000, 011, 101, 110, 111)

Expanding,

F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)

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