Answer:
55.32% probability that a late package was delivered by express delivery service 2
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Late delivery.
Event B: Service 2 was used.
A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery service 2.
100 - 35 = 65%.
So ![P(B) = 0.65](https://tex.z-dn.net/?f=P%28B%29%20%3D%200.65)
Service 2 has a record of 2.0% of packages being delivered late.
This means that ![P(A|B) = 0.02](https://tex.z-dn.net/?f=P%28A%7CB%29%20%3D%200.02)
Probability of a late delivery.
35% from service 1. Of those, 3% are late.
65% from service 2. Of those, 2% are late.
So
![P(A) = 0.35*0.03 + 0.65*0.02 = 0.0235](https://tex.z-dn.net/?f=P%28A%29%20%3D%200.35%2A0.03%20%2B%200.65%2A0.02%20%3D%200.0235)
What is the probability that a late package was delivered by express delivery service 2
55.32% probability that a late package was delivered by express delivery service 2
After calculating for ten minutes, I got 1. B and 2. D
Answer:
f(10) = 342
Step-by-step explanation:
f(x) = 3x² + 6x - 18
f(10 = 3(10)² + 6(10) - 18
f(10) = 3(100) + 60 - 18
f(10) = 300 + 60 - 18
f(10) = 360 - 18
f(10) = 342