Question

Y=5x+4 and 3x+2y=20 by using elimination​

Answer 1

Answer:

Step-by-step explanation:

 y = 5x + 4

-5x + y = 4 ----------------------(i)

3x + 2y = 20 --------------------(ii)

Multiply equation (i) by (-2)

(i)* (-2)     10x - 2y = -8

(ii)            3x   + 2y = 20    { Now add this two equations}

              13x           = 12      { -2y and 2y got eliminated}

                          x = 12/13

Plug in value of x in (i)

-5*12/13  + y = 4

-60/13 + y = 4

y = 4 + 60/13

$y=\frac{4*13}{1*13}+\frac{60}{13}\\\\=\frac{52}{13}+\frac{60}{13}\\\\=\frac{112}{13}\\\\=8\frac{8}{13}y=$