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maria [59]
3 years ago
5

HELP PLEASE!!! I can't figure it out

Mathematics
1 answer:
inysia [295]3 years ago
3 0

Answer:

x = 11

Step-by-step explanation:

The given angles would be alternate exterior angles and be congruent, thus

6x - 2 = 5x + 9 ( subtract 5x from both sides )

x - 2 = 9 ( add 2 to both sides )

x = 11

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What is x? x/3 +10=15<br> A.15 B.-8
Charra [1.4K]
X is 15because 15-10=5
x= 3*5
x=15
6 0
3 years ago
Read 2 more answers
Subtract. Write your answer in simplest form. 3\15 - 2\5
fiasKO [112]
Answer 1: 2/5= 6/15 3/15-6/15= -3/15
Answer 2: 7/10= 14/20
1/4= 5/20
difference- 9/20
Answer 3:
2 5/6= 17/6
3 2/5= 17/5
17/6 = 85/30
17/5= 102/30
187/30
Answer 4:
11/2
9/7
77/14
81/14
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Answer 5:
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8 0
3 years ago
Please help
Alekssandra [29.7K]

Answer:

25 in x 15 in

Step-by-step explanation:

Given:

  • Length = 3/5 the width
  • Area = 375 in²

Let width = x

Therefore, length = 3/5 x

First create an equation for the area of the picture based on the given information for its width and length:

\begin{aligned} \implies \textsf{Area of original picture} & = \sf width \times length\\& = x\left(\dfrac{3}{5}x\right)\\& = \dfrac{3}{5}x^2\end{aligned}

We are told the area of the enlarged picture is 375 in².  Therefore, substitute this into the equation and solve for x to find the width of the enlarged picture:

\begin{aligned}\textsf{Area} & = 375\\ \implies \dfrac{3}{5}x^2 & = 375\\ x^2 & =375 \cdot \dfrac{5}{3}\\ x^2 & =625\\ x & = \sqrt{625}\\ x& = 25\end{aligned}

Therefore, the width of the enlarged picture is 25 in.

Substitute the found value of x into the expression for length to find the length of the enlarged picture:

\begin{aligned}\sf Length & = \dfrac{3}{5}x\\\\\implies \sf Length & = \dfrac{3}{5}(25)\\\\& = 15\: \sf in\end{aligned}

Therefore, the dimensions of the enlarged picture are <u>25 in x 15 in</u>.  The width is 25 in and the length is 15 in, as the length is 3/5 of the width.

5 0
2 years ago
If <img src="https://tex.z-dn.net/?f=f%28x%29%3D%20%5Cfrac%7B1%7D%7Bx-2%7D%20" id="TexFormula1" title="f(x)= \frac{1}{x-2} " alt
Darina [25.2K]
I think, the answer will be -7

We have:
f(x)=1/(x-2)
g(x)
Then:
(fg)(x)=[1/(x-2)](g(x))=g(x)/(x-2)
Now; we calculate: (fg)`(x)
Remember: (u/v)=(u`v-vu´)/v²
Therefore:

(fg)´(x)=[g´(x)*(x-2) - 1*g(x)]/ (x-2)²
We know that:
g´(1)=-1
(fg)´(1)=6
Therefore:
6=[-1*(1-2)-g(1)]/(1-2)²
6=[1-g(1)]/1
6=1-g(1)
-g(1)=6-1
g(1)=-5

Answer: B. -5
4 0
4 years ago
Find the area of a rectangle &amp; triangle! NEED HELP ASAP
Cloud [144]

Answer:

For rectangle: A=wl

Step-by-step explanation:

Multiply the length by the with to find the answer

3 0
2 years ago
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