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sesenic [268]
3 years ago
12

Can someone please help me out

Mathematics
1 answer:
Paha777 [63]3 years ago
8 0

Answer:

D. 20.

Step-by-step explanation:

  1. -17 - -37 = 20.

These are all of the steps, to completely, get the correct answer to this question.

Hope this helps!!!

Kyle.

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Josephine decided to get this Platinum card since she saw the ads touting the "0% A.P.R. Platinum. Sign Up
agasfer [191]

Answer: A. Her A.P.R will change after six months and be between 15.24% to 23.24% assuming that she has been making on-time payments during those first six months.

Step-by-step explanation:

8 0
3 years ago
An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.
andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are E(1)= ^9C_2 places in which the other 2 red balls can be placed.

A red ball drawn third, there are E(3)= ^7C_2 places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are E(5)= ^5C_2 places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are E(7)= ^3C_2 places in which the other 2 red balls can be placed.

The total number of total event is S= ^{10}C_3

The probability that A selects the first red ball is

P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}

P(A \text{wins})=\frac{36+21+10+3}{120}

P(A \text{wins})=\frac{70}{120}

P(A \text{wins})=0.5833

6 0
3 years ago
Percentage grade averages were taken across all disciplines at a particular university, and the mean average was found to be 83.
Georgia [21]
Correct Ans:
Option A. 0.0100

Solution:
We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.

First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

z-score= \frac{90-83.6}{ \frac{8.7}{ \sqrt{10} } } \\  \\ 
z-score =2.326

So, 90 converted to  z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.

Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.
5 0
4 years ago
PLEASE HELP! I have made a pic of it. Hope you have a nice day
masha68 [24]
A is the answer 7th graders are not likely
8 0
2 years ago
What is the length of segment RS?
Evgesh-ka [11]

Answer:

3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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