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SSSSS [86.1K]
3 years ago
10

What is the answer to number 1

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
6 0
Would the common factor be 1?
edit
the least common is 1 and the most common is 2

thanks andreadiaz2003
spin [16.1K]3 years ago
4 0
2 because no other number besides 1 will go into 2 so the answer is 2.
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Bobby catches 8 passes in 3 football games. At this rate how many passes dose he catch in 15 games?expine
stepan [7]

Answer: 40

Step-by-step explanation:

I can see the answer is 40, but let's try to figure out how to do it.

I like to use the rule of 3. Let's put the number of passes on the left side and the number of games on the right side.

\frac{8}{x}=\frac{3}{15}

''x'' represents the number of passes in 15 games.

Solve for x;

x=\frac{15*8}{3}\\ x=\frac{120}{3}\\ x=40

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Answer: My thoughts on the loss of trees is quite disappointing due to the fact that we need them to survive. The loss of trees is not something good for the environment because many animals need it for shelters. It could cause animals to be endangered because they can’t hide from predators or hunters. Hopefully the trees will start increasing in 2020.

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Can someone help me for this?​
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8 0
2 years ago
When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let
kupik [55]

Answer:

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Step-by-step explanation:

The probability that the random variable X takes the value x is given by P(X=x) = 25Cx 0.05^x0.95^{25-x}. Then,

(a) P(X\leq) = (25C0)(0.05^0)(0.95^{25}) + (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23})=  0.873

(b) P(X\geq5) = 1-P(X\leq4) = 1 - (0.873 + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21})) = 1 - (0.873 + 0.12) = 0.007

(c) P(1\leqX\leq4) = (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23}) + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21}) = 0.715

(d) P(X=0) = (25C0)(0.05^0)(0.95^{25}) = 0.277  

(e) E(X) = np = (25)(0.05) = 1.25 and Sd(X) = \sqrt{Var(X)} = \sqrt{np(1-p)} = 1.09

8 0
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Answer:

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= 4×π×4²

= 64π

= 201.1 km² (rounded to the nearest tenth)

4 0
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