All categories

4 years ago

Round 3,590 to the nearest ten

Mathematics

2 answers:

Triss [41]4 years ago

7 0

i think the answer would be 4,000 (its been a long time since i have rounded)

tester [92]4 years ago

6 0

Note that the tens value. It is 9. Look at the number at the place value to the right of it. It is a 0. Because 0 is less than 5, round down.

3590 rounded to the nearest ten is 3590

hope this helps

You might be interested in

What are the last 2 digits of 7 to the power of 2018. This question was on a past exam paper.

Xelga [282]

Answer:

Step-by-step explanation:

Try finding pattern of last two digits of 7 to the power of some numbers.

7^1=07

7^2=49

7^3=343

7^4= 2301

7^5= 16807

so , the pattern is, 07,49,43,01

so, if we start writing all numbers from 1 to 2018 , four number in each line, 2018 will fall in the second column.

so it will have 49 as the last 2 digits [by seeing this pattern : 07,49,43,01 ]

6 0

3 years ago

Use models to prove that 3 (a+b) is equivalent to 3a + 3b.

mezya [45]

The 3 is distributed to the a+b inside the brackets........

5 0

4 years ago

Read 2 more answers

A sphere of radius r is cut by a plane h units above the equator, where

Anika [276]

Consider the top half of a sphere centered at the origin with radius $r$ , which can be described by the equation

$z=\sqrt{r^2-x^2-y^2}$

and consider a plane

$z=h$

with $0$ . Call the region between the two surfaces $R$ . The volume of $R$ is given by the triple integral

$\displaystyle\iiint_R\mathrm dV=\int_{-\sqrt{r^2-h^2}}^{\sqrt{r^2-h^2}}\int_{-\sqrt{r^2-h^2-x^2}}^{\sqrt{r^2-h^2-x^2}}\int_h^{\sqrt{r^2-x^2-y^2}}\mathrm dz\,\mathrm dy\,\mathrm dx$

Converting to polar coordinates will help make this computation easier. Set

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\var\phi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$

Now, the volume can be computed with the integral

$\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_0^{\arctan\frac{\sqrt{r^2-h^2}}h}\int_{h\sec\varphi}^r\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

You should get

$\dfrac{2\pi}3\left(r^3\arctan\dfrac{\sqrt{r^2-h^2}}h-\dfrac{h^3}2\left(\dfrac{r\sqrt{r^2-h^2}}{h^2}+\ln\dfrac{r+\sqrt{r^2-h^2}}h\right)\right)$

5 0

3 years ago

21 = m + 9 m = 11 is it a solution

Zarrin [17]

No because 21=(11)+9
21 can’t equal to 20

7 0

4 years ago

Keisha drinks 0.65 of milk every day. How much milk does she drink in 13 days?

ivanzaharov [21]

The answer is 8.45..... you times 0.65 by 13

4 0

3 years ago

Read 2 more answers