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BigorU [14]
2 years ago
11

What is 2x + 7x + 8a + 9a

Mathematics
2 answers:
nlexa [21]2 years ago
8 0

Answer: 9x + 17a

Step-by-step explanation:

2x + 7x + 8a + 9a

2x+7x= 9x

8a+9a= 17a

= 9x +17a

lisabon 2012 [21]2 years ago
7 0

Answer:

9x + 17a

Step-by-step explanation:

9x + 17a. (A side note is that you can't add x and a together because they are different variables.)

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Simplify the following expression
timama [110]

Answer: 0.25 or 1/4

Step-by-step explanation:

1/2*2 = 1/2^2 = 1/4

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3 years ago
Subtract I need help^_^
trapecia [35]
The answer to this subtraction is d
6 0
3 years ago
Could somebody please answer these four questions with simple yet explanatory answers?
Kamila [148]
1) Surface Area = 2(lw + lh + wh)
2(4*5+4*9+5*9) =202in^2
Surface Area=202in^2
Lateral Area= Perimeter of base * height
5+5=10  <--width+width
4+4=8 <---length + length 
10+8=18  <--total perimeter
18 * 9=162in^2  <--multiplied the height +perimeter of base  
Lateral Area=162in^2

2) Same concept as the previous one
 Surface Area = 2(lw + lh + wh)
2(4*2+4*5+5*2) =76in^2
Surface Area= 76in^2

Lateral Area
Lateral Area= Perimeter of base * height
4+4=8
2+2=4
8+4=12
12 x 5=60
Lateral Area= 60in^2  
7 0
3 years ago
Read 2 more answers
If the distance covered by an object in time t is given by s(t)=t^2+5t , where s(t) is in meters and t is in seconds, what is th
alisha [4.7K]

Answer:

E. 44 meters

Step-by-step explanation:

The function that models the distance covered by the object is

s(t)=t^2+5t

where s(t) is in meters and t is in seconds.

The distance covered by the object after 1 second is

s(1)=1^2+5(1)=6m

The distance covered by the object after 1 second is

s(1)=5^2+5(5)=50m

The distance covered between 1 second and 5 seconds is

50-6=44m

6 0
3 years ago
PLEASE help due today Geometry
irina1246 [14]

\\ \sf\Rrightarrow \dfrac{15}{20}=\dfrac{21}{28}

\\ \sf\Rrightarrow \dfrac{1}{4}=\dfrac{1}{4}

Hence they are similar

#2

  • <A=<H
  • And ratio of sides are same

Hence both triangles are similar by SAS property

#3

\\ \sf\Rrightarrow ∆KDH\sim ∆ABD

8 0
2 years ago
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