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Nookie1986 [14]
3 years ago
8

What is the value of the underlined digit 0.812 as a fraction

Mathematics
2 answers:
denis23 [38]3 years ago
8 0

I unsure about which digit is underlined but suppose it is all three 812. Then the correct representation as a fraction is 812/1000. If the undwrlined digit was just the 8 it would be 8/10. 1 would be 1/100, and 2 would be 2/1000.

MAVERICK [17]3 years ago
4 0
The answer is 812/100
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How would I solve this equation by showing my worki on each side?<br> X divided by 10= 7
Sav [38]

Answer:

x=70

Step-by-step explanation:

x/10=7

First you need to get the x by itself, so you should do the opposite of what is happening to the x.

In this case the x is being divided so you would need to multiply.

So multiply the x by 10 and this gets it by itself.

But you have to do to one side what you do to the other.

So multiply the other side by 10 as well!

This equals x=70

To show work on both sides, show the multiplication of both sides by 10

4 0
3 years ago
Find the slope of (-6,2) and (-4,13)
rewona [7]

We can use the points (-6, 2) and (-4, 13) to solve.

Slope formula: y2-y1/x2-x1

= 13-2/-4-(-6)

= 11/2

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6 0
3 years ago
What’s the answer ?
makvit [3.9K]

Answer:(D) is the answer

Step-by-step explanation:

for every cup grandma uses 3/4 of a cup of strawberry

6 0
2 years ago
A store sells six cupcakes for $7. How much do 18 cupcakes cost?
ollegr [7]

Answer:

21 cupcakes

Step-by-step explanation:

6 = $7

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18 = $21

7 0
2 years ago
Read 2 more answers
6. If the net investment function is given by
Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated  capital for the period.

  • (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

  • (b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

I(t) = 100 \cdot e^{0.1 \cdot t}

(a) The capital formation is given as follows;

\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot  e^{0.1 \cdot t}} + C

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore,  for the three years; Year 3, year 4, and year 5, we have;

\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

\displaystyle  \mathbf{\left[1000 \cdot  e^{0.1 \cdot t}} + C \right]^t_0} = 100,000

Which gives;

\displaystyle 1000 \cdot  e^{0.1 \cdot t}} - 1000 = 100,000

\displaystyle \mathbf{1000 \cdot  e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000

\displaystyle e^{0.1 \cdot t}} = 101

\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

6 0
2 years ago
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