Question

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Answer 1

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad \sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}} \\\\\\ |a|\implies \begin{cases} +a\\ -a \end{cases}\implies \pm a\\\\ -------------------------------\\\\ (16x^2)^{\frac{1}{2}}\implies \pm\sqrt[2]{(16x^2)^1}\implies \pm\sqrt{4^2x^2}\implies \pm\sqrt{(4x)^2}\implies \pm 4x \\\\\\ \begin{cases} +4\\ -4 \end{cases}\implies |4x|$