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deff fn [24]
2 years ago
14

Find the length of AB. 6 30 AB=[?]in

Mathematics
1 answer:
Verdich [7]2 years ago
5 0

Answer:

AB ≈ 3.14 in

Step-by-step explanation:

arc AB is calculated as

AB = circumference of circle × fraction of circle

     = 2πr × \frac{30}{360}

     = 2π × 6 × \frac{1}{12}

     = 12π × \frac{1}{12}

     = π ≈ 3.14 in ( to the nearest hundredth )

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7(1-2x)=-x+33<br>solve with every step
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7(1 - 2x) = -x + 33

Distribute 7 inside the parentheses.

7 - 14x = -x + 33

Subtract 7 from both sides.

-14x = -x + 26

Add x to both sides.

-13x = 26

Divide both sides by -13.

x = -2

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3 years ago
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8 + 6x - 10x = 16 - 8x
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The answer is x=2

Remember, first add/substract the like terms, in this case 6x-10x to get -4x. Then, add 8x to negative 8x to cancel it out and do the same thing to -4x. Do this with all your terms and you should get 4x=8. Then divide both sides by 4 to get x=2.
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1. I am looking into a fish tank. I see 5 red fish for every 2 blue fish. If there are 22 red fish,
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11?

Step-by-step explanation:

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Answer:

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2 years ago
Cos (90-theta) • cosec90-theta) =tano. How?​
denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

  • \cos (90 - \alpha  ) = \sin \alpha  or  \sin(90 - \alpha ) = \cos\alpha
  • cosec \: (90 - \alpha  ) = \sec\alpha   or  \sec(90 - \alpha ) = cosec\:\alpha

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

  • <u></u>\sin \alpha = \frac{1}{cosec \: \alpha }  or  cosec \: \alpha  = \frac{1}{\sin \alpha }
  • <u></u>\cos \alpha = \frac{1}{\sec \alpha }  or  \sec \alpha = \frac{1}{\cos \alpha }

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

\cos (90 - \alpha ) \times cosec(90 - \alpha )

=> sin\alpha  \times \sec\alpha

=> \sin\alpha  \times \frac{1}{\cos\alpha }

=> \frac{\sin\alpha }{\cos\alpha }

=> \tan\alpha = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

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3 years ago
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